If you mean quadrilateral ABCD then by using the cosine rule diagonal AC equals 5.71 cm and diagonal BD equals 6.08 cm both rounded to two decimal places.
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Opposite sides of a parallelogram are equal. So ab = dc and ad = bc. But you are also told that ab = bc. So all four sides are equal. Opposite angles of a parallelogram are equal. So abc =90 degrees implies that cda is 90 degrees. The remaining two angles add up to 360 - (abc + cda) = 180 degrees and both are equal. So they, too , must be 90 degrees each. So all four angles are equal. A parallelogram with four equal sides and four equal angles is called a square.
x = 0.125 ( BC - 7 )
Commutativity.
25 units
25
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Given ef is the midsegment of isosceles trapezoid abcd bc equals 17x ef equals 22.5x plus 9 and ad equals 30x plus 12 find ad?
Anything you like (as long as it is > -16 so that BC > 0). In a parallelogram, adjacent sides do not impose any restrictions on one another.
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bc = ad = 75 Tan adb = 160/75 = 2.1333 (4dp), so angle adb = 64.885°.
If you mean quadrilateral ABCD then by using the cosine rule diagonal AC equals 5.71 cm and diagonal BD equals 6.08 cm both rounded to two decimal places.
Assuming ABCD marks the four corners, the perimeter = sum of the four sides = (AB + BC + CD + DA) where AB == the side from A to B etc.
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First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31