derivation of pedal equation
http://en.wikipedia.org/wiki/Navier-Stokes_equations Please go to this page.
They could be the coordinates of a straight line equation
Yes if it is a straight line equation
You can either measure or estimate the coordinates visually from the graph, or solve the equation underlying the graph.
derivation of pedal equation
The graph (on Cartesian coordinates) of a quadratic equation is a parabola.
-4x + 9y = 0 is the equation of a line in the Cartesian plane and the coordinates of any of the infinite number of points on that line will satisfy the equation.
the equation that convert from cartesian to polar coordinates and vice versa r = sqrt (x*x+y*y); phi = atan2 (y, x); x = r*cos (phi); y = r*sin (phi);
it is easy you can see any textbook........
The equation in Cartesian coordinates is x2 + y2 = 6 But much simpler are the polar coordinates: r = 6 and 0 ≤ q < 360 degrees.
http://en.wikipedia.org/wiki/Navier-Stokes_equations Please go to this page.
Gibbs-duhem-margules equation and its derivation
If you put an 'equals' sign ( = ) between the 'By' and the 'Cz', you have the generic equation for any straight line in 3-dimensional Cartesian coordinates.
It is the straight line equation that can be used to locate coordinates of x and y on the Cartesian plane
The y-intercept (or y-intercepts) of an equation is where x = 0. Replace x with zero in the equation, and solve for y.The answer depends on what information you are given - and in what form. If the equation of the curve is given in polar coordinates or in parametric form, the process is quite different to that required when given the Cartesian equation.
x2+y2=2y into polar coordinates When converting Cartesian coordinates to polar coordinates, three standard converstion factors must be memorized: r2=x2+y2 r*cos(theta)=x r*sin(theta)=y From these conversions, you can easily get the above Cartesian equation into polar coordinates: r2=2rsin(theta), which reduces down (by dividing out 1 r on both sides) to: r=2sin(theta)