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x intercept = (5, 0)

y intercept = (0, -20)

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Q: How do you find x and y intercepts to this 4x -20?
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Continue Learning about Geometry

Find the x and y-intercepts y equals 4x-14?

18


A rectangle has width represented by x and length represented by 4x If the area of the rectangle is 80 find the value of x What is x?

length is 4x and width is x: 4x*x = 80 4x2 = 80 Divide both sides by 4: x2 = 20 Square root both sides: x = 4.472135955


What are the intercepts for the line -4x y 8?

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. If your question is not answered, please resubmit it, spelling out the symbols as "plus", "minus", "equals" etc. Also use ^ to indicate powers (x^2) or x-squared.Restate the question: What are the intercepts of the line -4x + y = 8?To find the y-intercept, let x=0: -4(0)+y=8 y=8To find the x-intercept, let y=0: -4x+(0)=8 -4x=8 -4x/(-4)=8/(-4) x=-2With a little practice, and if the numbers are 'nice', you can almost do this by just looking at the equation, or you can think of (0,_),(_,0). My students call this "googly eyes"!Also note that most texts define an intercept as a number ("the y-intercept is 8"), but it is rare to consider "The y-intercept is (0,8)." to be correct.


How are solution and x-intercept and zero of a function and and root related?

solutions are the well solution to the problem. X-intercepts are wherever a graph cross the x axis, which are hte solutions when you have to find out what x is, zeros are pretty much the same thing although i think that include y-intercepts as well..... not sure. and roots are the same thing as x-intercepts. so they are all more or less the same thing


What represents the vertex and two x-intercepts of y equals x2-2x-35?

(1,-36); -5 and 7y = x2-2x-35; f(x) = ax2+bx+cvertex, method 1:There is a formula for the vertex, if you can remember it. (h,k) = [-b/2a, f(-b/2a)].-b/2a = 2/2x1 = 2/2 = 1. f(1) = 12-2x1-35 =1-2-35 = -36. The vertex is (1,-36).vertex, method 2:Otherwise you complete the square to convert to the vertex form, y = a(x-h)2 + k. Complete the square for x2-2x: the constant term will be (-2/2)2 = (-1)2 = 1.y = (x2-2x+1)-1-35 = (x-1)2 -36 ==> The vertex is (h,k) = (1,-36).x-intercepts, method 1:To find the x-intercepts, let y=0: 0 = x2-2x-35 (x-7)(x+5) = 0 x-7=0 or x+5=0 x=7 or x=-5. The intercepts are -5 and 7.x-intercepts, method 2:There is also a nice trick to find the intercepts: 36 = 62. the intercepts are 1+/- 6 = 7 and -5.