Use a calculator. There is no simple way to calculate it.
its the tangent of the angle the slope makes with the x-axis
Take the inverse tangent -- tan-1(opposite side/adjacent side)
31 degrees
236-124/2=56 degrees
Although you haven't expressed it too clearly in your question, I think what you may belooking for is the angle whose tangent is 4,900, and the angle whose tangent is 19,600 .The problem is that the tangent of 89 degrees is about 57.3, and every numberfrom 57.3 all the way up to 'infinity' is the tangent of an angle somewhere in thatlast degree, between 89 and 90 . . . They really bunch up in there !4,900 is the tangent of 89.9883 degrees. (rounded)19,600 is the tangent of 89.9971 degrees. (rounded)
budosnp
Cotangent is ' 1/tangent' or ' Cosine / Sine'.
its the tangent of the angle the slope makes with the x-axis
The tangent-tangent angle is formed by two tangents drawn from a point outside a circle to points on the circle. To find the measure of the tangent-tangent angle, you take half the difference of the intercepted arcs. In this case, the arcs measure 135 degrees and 225 degrees. Therefore, the measure of the tangent-tangent angle is (\frac{1}{2} (225^\circ - 135^\circ) = \frac{1}{2} (90^\circ) = 45^\circ).
The tangent secant angle is the angle between the tangent to a circle and the secant, when the latter is extended.
Take the inverse tangent -- tan-1(opposite side/adjacent side)
31 degrees
45 degrees
196-164/2= 16
236-124/2=56 degrees
the tangent of an angle is equal to the length of the opposite side from the angle divided by the length of the side adjacent to the angle.
The angle between the radius and the tangent is a right angle of 90 degrees.