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Although you haven't expressed it too clearly in your question, I think what you may be
looking for is the angle whose tangent is 4,900, and the angle whose tangent is 19,600 .
The problem is that the tangent of 89 degrees is about 57.3, and every number
from 57.3 all the way up to 'infinity' is the tangent of an angle somewhere in that
last degree, between 89 and 90 . . . They really bunch up in there !
4,900 is the tangent of 89.9883 degrees. (rounded)
19,600 is the tangent of 89.9971 degrees. (rounded)
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A block is at rest on an inclined plane. Find the critical angle at which the box beigns to slide?
tan-1(MUs)= critical angle
How do you find the measure of a tangent angle?
Take the inverse tangent -- tan-1(opposite side/adjacent side)
The tan of a 45 degree angle?
1.00
Find tan if an angle in standard position and the point with coordinates negative twelve and positive five lies n the terminal side of the angle?
If you draw this angle in a coordinate system, a right triangle is formed in the second quadrant, with length legs 12 and 5 units. If you label with O the angle that is formed by the terminal side and y-axis, you have tan O = 12/5 and O = tan-1 12/5 = 67.38 degrees Thus, the given angle has a measure of 157.38 degrees (90 + 67.38).
The tangent of an angle is 0.8. What is the measure of the angle to the nearest tenth?
It is: tan^-1*(0.8) = 38.7 degrees
How would you find out the sin tan and cos of right angle triangle?
sin, tan and cos can be defined as functions of an angle. But they are not functions of a triangle - whether it is a right angled triangle or not.
Can't find the tan angle?
I can't either. Don't know what a "tan angle" is, so don't know what I'm looking for. It might be right here under my nose.
What is the half angle formula to find the exact value for tan 165?
tan u/2 = sin u/1+cos u
A block is at rest on an inclined plane. Find the critical angle at which the box beigns to slide?
tan-1(MUs)= critical angle
What is the height of a building when the distance between its angles of elevation which are 29 degrees and 37 degrees is 30 meters on level ground?
Using trigonometry its height works out as 63 meters to the nearest meter. -------------------------------------------------------------------------------------------------------- let: h = height building α, β be the angles of elevation (29° and 37° in some order) d be the distance between the elevations (30 m). x = distance from building where the elevation of angle α is measured. Then: angle α is an exterior angle to the triangle which contains the position from which angle α is measured, the position from which angle β is measured and the point of the top of the building. Thus angle α = angle β + angle at top of building of this triangle → angle α > angle β as the angle at the top of the building is > 0 → α = 37°, β = 29° Using the tangent trigonometric ratio we can form two equations, one with angle α, one with angle β: tan α = h/x → x = h/tan α tan β = h/(x + d) → x = h/tan β - d → h/tan α = h/tan β - d → h/tan β - 1/tan α = d → h(1/tan β - 1/tan α) = d → h(tan α - tan β)/(tan α tan β) = d → h = (d tan α tan β)/(tan α - tan β) We can now substitute the values of α, β and x in and find the height: h = (30 m × tan 37° × tan 29°)/(tan 37° - tan 29°) ≈ 63 m
What is the approximate height of a building when the angle of elevation at the top of a building is 34 degrees and at a point 80 feet closer the angle of elevation is 45 degrees?
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (80 ft × tan 45° × tan 34°)/(tan 45° - tan 34°) ≈ 165.78 ft
What is tan on a scientific calculator?
It is a trigonometric equation for a right triangle, to find a non-right-angle angle. Using SOHCAHTOA, it is the opposite side divided by the adjacent angle
Find the angle with tangent ratio of 0.4877?
tan-1(0.4877) = 25.99849161 or about 26 degrees
What is the height of a building if the angle of elevation to the top from a point on the ground is 31.4 degrees and from 53 feet further back it is 26.4 degrees?
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (53 ft × tan 31.4° × tan 26.4°)/(tan 31.4° - tan 26.4°) ≈ 140.87 ft
What is the height of a hill when the angle of elevation to the top of the hill from a point is 50 degrees and is 30 degrees from a point 40 feet farther away from the base of the hill?
It can be shown that:height = (d tan α tan β)/(tan α - tan β)where: α is the angle closest to the objectβ is the angle further away from the objectd is the distance from the point of angle α to the point of angle βThus: height = (40 ft × tan 50° × tan 30°)/(tan 50° - tan 30°) ≈ 44.80 ft
What is the angle formed between two lines?
If you know the gradient for a line (the m in y = mx + c) then tan-1 (m) will give you the angle between the line and the x axis. So do tan-1 for both gradients and subtract to find angle between the lines.
If you assume that angle A is an acute angle and tan A equals 1.230 what is the measure of angle A?
50.9
