Although you haven't expressed it too clearly in your question, I think what you may be
looking for is the angle whose tangent is 4,900, and the angle whose tangent is 19,600 .
The problem is that the tangent of 89 degrees is about 57.3, and every number
from 57.3 all the way up to 'infinity' is the tangent of an angle somewhere in that
last degree, between 89 and 90 . . . They really bunch up in there !
4,900 is the tangent of 89.9883 degrees. (rounded)
19,600 is the tangent of 89.9971 degrees. (rounded)
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tan-1(MUs)= critical angle
Take the inverse tangent -- tan-1(opposite side/adjacent side)
1.00
If you draw this angle in a coordinate system, a right triangle is formed in the second quadrant, with length legs 12 and 5 units. If you label with O the angle that is formed by the terminal side and y-axis, you have tan O = 12/5 and O = tan-1 12/5 = 67.38 degrees Thus, the given angle has a measure of 157.38 degrees (90 + 67.38).
It is: tan^-1*(0.8) = 38.7 degrees