With a pair of scissors by cutting off two off its corners leaving you with 2 triangles and 1 pentagon.
1 triangle is formed.
1 vertex less than a hexagon is a pentagon. 2 angles more than a triangle is a pentagon.
a pentagonal pyramid
If the pentagon is a regular pentagon, then each of the central angles (formed by joinning the center with the vertices) is72⁰ (1/5 of 360⁰). So that 5 congruent isosceles triangle are formed, with base angles of 54⁰. If we draw the height, of these triangles (from the center to the sides of the pentagon), 10 congruent right triangles are formed. Let denote with: b the sides of the pentagon, and h the height. In one of the right triangles we have: tan 54⁰ = h/(b/2) tan 54⁰ = 2h/b 1.38 = 2h/b 2h = 1.38b h = (1.38/2)b h = .69b So that, h/b = .69b/b = .69
2 small triangles 1 med. triangle 2 large triangles 1 parallelogram and a square
By cutting off two of its corners which will leave you with 2 triangles and 1 pentagon.
1 triangle is formed.
Consider the pentagon ABCDE. By drawing diagonals from B, we get: 1. Triangle ABE 2. Triangle BDE 3. Triangle BCD -Ashwin Hendre
You didn't say it was a regular pentagon. For an arbitrary pentagon, you would calculate its area as you would for any polygon: divide it up into triangles, and add up the areas of the triangle. The area of a triangle is 1/2 times the base times the height, the height being the length of the perpendicular dropped to the base from the opposite vertex.
A regular pentagon has five (5) equilateral triangles within it. Find the area of each triangle (1/2bh where b is the base of the triangle or the length of a side of the pentagon, and h is the height of the triangle or the apothem of the pentagon) and multiply the area of the triangle times five (5).
To create a pentagon using 6 tangram pieces, start by selecting the shapes: 2 large triangles, 1 medium triangle, and 3 small triangles. Arrange the two large triangles to form a base, positioning the medium triangle on top to create the upper part. Use the small triangles to fill in the gaps and complete the pentagon shape. Adjust their positions until the outline resembles a pentagon.
With a good ol' fashion pen. Impossible
You'd have to have fractional parts of triangles. Each group would have 1 and 1/3 triangle.
One possible way to divide a pentagon into five parts is (assuming this is a convex pentagon) to start by placing a dot directly in the center. Then, draw a 5 lines from that center dot connecting to the 5 points around the edge of the pentagon. You should now have 5 triangles instead of 1 pentagon.
there are 27 triangles in a triangle
Three triangles
The formula is A=1/2bh b=base of triangle h=height of triangle A=area 1/2=divide base times height by 2