Using Pythagoras; theorem it is 12 Times Square root of 2 which is about 17 cm rounded to the nearest integer
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Using Pythagoras' theorem: 8 times the square root of 2 which is about 11,3137085 cm
Designate the length by L. From the Pythagorean theorem, the length of the diagonal of a square, which divides the square into two right triangles, each with sides L (and the diagonal as hypotenuse to each right triangle), is square root of 2L2 = 4 (from the problem statement). Squaring both sides separately yields 2L2 = 16 or L = square root of 8 = 2 (square root of 2).
To find the diagonal of a square, we can use the formula for the diagonal of a square, which is d = s√2, where d is the diagonal length and s is the side length of the square. Given that the area of the square is 36, we can find the side length by taking the square root of the area, which is √36 = 6. Substituting s = 6 into the formula, we get d = 6√2. Therefore, the diagonal of the square with an area of 36 is 6√2 units.
Each side = sqrt (182 / 2) = sqrt (162) = 12.72792 metres
The diagonal of a square whose area is 36 is the square root of 72, or about 8.49. Since the area of a square is side(squared), then the sides are each 6. Then since a(squared) + b(squared) = c(squared), for a triangle (the diagonal), you get the square root of 72.