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Let the number of sides be x and use the diagonal formula:
1/2*(x2-3x) = 104
Multiply both sides by 2:
x2-3x = 208
Subtract 208 from both sides:
x2-3x-208 = 0
Solving the above by means of the quadratic equation formula gives x a value of -13 and 16 so it must have 16 sides
Check: 1/2*(162-(3*16)) = 104 diagonals
What else can I help you with?
How yo find the formula on how to solve the number of diagonals in a polygon?
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
How many diagonals does a 11 sided polygon have?
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
How do you find the number of diagonals in a polygon?
Use the formula of: 0.5*(n2-3n) whereby n is the number of sides of the polygon
How many sides does a polygon have if it has 495 diagonals?
nope.aviImproved Answer:-33 because 1/2*(332-99) = 495
A polygon has 14 diagonals how many sides does it have?
To determine the number of sides in a polygon with 14 diagonals, we can use the formula for the number of diagonals in a polygon: D = n(n-3)/2, where n is the number of sides. By setting D = 14 and solving for n, we get n(n-3)/2 = 14. Simplifying this equation, we find that n^2 - 3n - 28 = 0. Factoring this quadratic equation, we get (n-7)(n+4) = 0. Therefore, the polygon has either 7 or -4 sides. Since the number of sides cannot be negative, the polygon must have 7 sides.
How yo find the formula on how to solve the number of diagonals in a polygon?
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
How can you find the number of diagonals in a polygon?
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon
WHAT IS THE ANSWER TOD12N(N-3) GIVES THE NUMBER OF DIAGONALS d FOR A POLYGON WITH N SIDES.. use THIS EQUATION TO FIND THE NUMBER OF DIAGONALS FOR POLYGON THAT HAS 13 SIDES .SOLVE?
65
How many diagonals does a 11 sided polygon have?
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
What is the formula to find diagonals in polygon?
0.5*(n2-3n) where n is equal to the number of sides of the polygon
How do you find the number of diagonals in a polygon?
Use the formula of: 0.5*(n2-3n) whereby n is the number of sides of the polygon
What rule can be used to find number of diagonals that can be drawn from one vertex of regular polygon?
You can use the formula D=S-2 where D is the number of possible diagonals and S is the number of sides the polygon has.
How many sides does a polygon have if it has 495 diagonals?
nope.aviImproved Answer:-33 because 1/2*(332-99) = 495
How do you find the number of sides of a polygon given the number of diagonals?
Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals. Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.
Where d is the number of diagonals of a polygon with n sides find d if equals 20?
1/2*(n2-3n) = number of diagonals 1/2*(202-60) = 170 diagonals
Where d is the number of diagonals of a polygon with n sides find d if n equals 20?
1/2*(n2-3n) = number of diagonals 1/2*(202-60) = 170 diagonals
A polygon has 14 diagonals how many sides does it have?
To determine the number of sides in a polygon with 14 diagonals, we can use the formula for the number of diagonals in a polygon: D = n(n-3)/2, where n is the number of sides. By setting D = 14 and solving for n, we get n(n-3)/2 = 14. Simplifying this equation, we find that n^2 - 3n - 28 = 0. Factoring this quadratic equation, we get (n-7)(n+4) = 0. Therefore, the polygon has either 7 or -4 sides. Since the number of sides cannot be negative, the polygon must have 7 sides.
