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How do you find the number of sides a polygon has when it has 104 diagonals?
Wiki User
∙ 11y ago
Let the number of sides be x and use the diagonal formula:
1/2*(x2-3x) = 104
Multiply both sides by 2:
x2-3x = 208
Subtract 208 from both sides:
x2-3x-208 = 0
Solving the above by means of the quadratic equation formula gives x a value of -13 and 16 so it must have 16 sides
Check: 1/2*(162-(3*16)) = 104 diagonals
Wiki User
∙ 11y ago
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How yo find the formula on how to solve the number of diagonals in a polygon?
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
How many diagonals does a 11 sided polygon have?
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
How do you find the number of diagonals in a polygon?
Use the formula of: 0.5*(n2-3n) whereby n is the number of sides of the polygon
How many diagonals does a 30 sided polygon have?
The formula used to find the number of diagonals in a polygon is n(n-3)/2. 30 x 27/2 = 810/2 = 405 diagonals.
How do you find a number of sides of a polygon with the measure of its interior angle?
If its a regular polygon then 180-interior angle and divide the answer into 360 which will give the number of sides of the polygon.
How yo find the formula on how to solve the number of diagonals in a polygon?
It is: 0.5*(n2-3n) = diagonals whereas 'n' is the number of sides of the polygon
WHAT IS THE ANSWER TOD12N(N-3) GIVES THE NUMBER OF DIAGONALS d FOR A POLYGON WITH N SIDES.. use THIS EQUATION TO FIND THE NUMBER OF DIAGONALS FOR POLYGON THAT HAS 13 SIDES .SOLVE?
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How can you find the number of diagonals in a polygon?
The formula is: 0.5*(n2-3n) where n is the number of sides of the polygon
How many diagonals does a 11 sided polygon have?
You can find the number of diagonals in a polygon using the formula n(n-3)/2, where n is the number of sides. Therefore an 11 sided polygon has 44 diagonals.
What is the formula to find diagonals in polygon?
0.5*(n2-3n) where n is equal to the number of sides of the polygon
How do you find the number of diagonals in a polygon?
Use the formula of: 0.5*(n2-3n) whereby n is the number of sides of the polygon
What rule can be used to find number of diagonals that can be drawn from one vertex of regular polygon?
You can use the formula D=S-2 where D is the number of possible diagonals and S is the number of sides the polygon has.
How do you find the number of sides of a polygon given the number of diagonals?
Using the formula (x)(x-3)/2 = Diagonals ; simply replace the diagonals with the number of diagonals you're given. Then, you'll havev (x)(x-3)/2 = Diagonals. Simplify it, and you'll be given x(power of 2) - 3X = (2)(Diagonals). Subtract the amount of diagonals from both sides, and you'll have x(power of 2) - 3X - 2Diagonals = 0. From there, use the quadratic formula to find the number of sides the polygon has.
Where d is the number of diagonals of a polygon with n sides find d if equals 20?
1/2*(n2-3n) = number of diagonals 1/2*(202-60) = 170 diagonals
Where d is the number of diagonals of a polygon with n sides find d if n equals 20?
1/2*(n2-3n) = number of diagonals 1/2*(202-60) = 170 diagonals
How do you find the diagonals in a pentagon?
Use the formula: 0.5*(n2-3n) whereas 'n' is the number of sides of the polygon So: 0.5*(25-15) = 5 diagonals
What is the formula to find the diagonal of trapezoid?
The formula for finding the diagonals of any polygon is: 0.5*(n2-3n) where n = the number of sides. A trapezoid has 4 sides so: 0.5*(16-12) = 2 diagonals
