The standard form of a hyperbola in an x-y plot is (x-m)2/a2 - (y-n)2/b2 = +/- 1 (meaning either + or -), where (m,n) is the point of symmetry.
Let us take the case of +1 on the right-hand side.
Expanding the equation, we have
b2x2 - x * (2mb2) - a2y2 + y * (2na2) = a2b2 - b2m2 + a2n2
You have to match the coefficients of your equation to the ones above.
Let us assume your equation is x2 - y2 = 1, which will be trivial to do.
Matching the coefficients, you have m = 0 = n and a = +/-1 = b (insufficient information to determine + or -).
Another simple example for your equation: 9x2 - 18x - 4y2 - 8y = 31.
Matching coefficients exactly, we have
b2 = 9 -- (1)
-2mb2 = -18 -- (2)
-a2 = -4 -- (3)
2na2 = -8; and -- (4)
a2b2 - b2m2 + a2n2 = 31 -- (5)
(1) is simplified to b = +/-3 (no way knowing + or -)
(3) is simplified to a = +/-2
(1) substituted into (2), (2) becomes m = 1
(3) substituted into (4), (4) becomes n = -1
Substituting (1-4) into 5, we have the LHS = 36 - 9 + 4 = 31 = RHS.
For our convenience, if +/- cannot be determined, take the + for the equation coefficients. Hence, a = 2 and b = 3.
Q.E.D.
In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.
Solve the equation for ' y '.
Since we know the slope, m = 5/3, and the y-intercept 1/2, we arw able to write the equation of the line in the slope-intercept form, y = mx + b, so we have y = (5/3)x + 1/2.The standard form of the equation of the line is Ax + By = C.y = (5/3)x + 1/2y - y - 1/2 = (5/3)x - y + 1/2 - 1/2-1/2 = (5/3)x - y or(5/3)x - y = -1/2Thus, the standard form, Ax + By = C, of the equation of the line is (5/3)x - y = -1/2.
The graph of a quadratic function is always a parabola. If you put the equation (or function) into vertex form, you can read off the coordinates of the vertex, and you know the shape and orientation (up/down) of the parabola.
look for the interceptions add these and divide it by 2 (that's the x vertex) for the yvertex you just have to fill in the x(vertex) however you can also use the formula -(b/2a)
There are different standard forms for different things. There is a standard form for scientific notation. There is a standard form for the equation of a line, circle, ellipse, hyperbola and so on.
A hyperbola is another form of a conical section graph like a parabola or ellipse. Its general form is x^2/a - y^2/b = 1.
y2-3x2+6x+6y= 18 is in standard form. The vertex form would be (y+3)2/24 - (x-1)2/8 = 1
In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.
A standard form of a linear equation would be: ax + by = c
5
The y-intercept is c in the standard form. The x-intercept is -c/m.
The standard form of an equation is Ax + By = C. In this type of equation, x and y are variables while A, B, and C are integers.
Solve the equation for ' y '.
To convert a quadratic equation from standard form (ax^2 + bx + c) to factored form, you first need to find the roots of the equation by using the quadratic formula or factoring techniques. Once you have the roots, you can rewrite the equation as a product of linear factors, such as (x - r1)(x - r2), where r1 and r2 are the roots of the equation. This process allows you to express the quadratic equation in factored form, which can be useful for solving and graphing the equation.
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By using Cartesian equations for circles on the Cartesian plane