For e.g we draw a rectangle with length and width of 4cm and 3cm respectively.
So the diagonal would be of 5cm(using Pythagoras theorem) and area 12cm^2.
Now using algebra we can find the dimensions of the rectangle,Look below:
let length=x
let width=y
so: x*y=12----(1)
x^2+y^2=5^2----(2)
x^2+y^2=25
Now simplifying the above equations:
x^2=25-y^2
---->x^2*y^2=144
---->(25-y^2)*y^2=144
25y^2-y^4=144
y^4-25y^2+144=0
let y^4=z^2
so:
z^2-25z+144=0
by simplifying the above quadratic equation:
z=(25+(25^2-4(1)(144))^(1/2))/2(1) , z= (25-(25^2-4(144))^(1/2))/2
z=16, z=9
when z=16, when z=9
so y=4 ,so y=3
Now verifying which magnitude is correct for y:
12/4=x ,12/3=x
x=3 not correct, because y>x x=4 is correct, because x>y
The width will be 30cm
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The diagonal is 20.
The diagonal is 3.61cm
If by that you mean knowing only the diagonal and the width, then by the formula a2+b2=c2, where a is the length, b the width and c the diagonal. To find the width b, you need to calculate sqrt(c2-a2). For example, the width of a rectangle with length 3 and diameter 5 is sqrt(52-32)=4
You square the width and subtract it from the diagonal squared. Then find the square root of this number, this number is now the length.
With Pythagoras' theorem: diagonal2- length2 = width2
You CAN'T calculate the perimeter of a rectangle, knowing only its diagonal. You do need some additional information about the rectangle - such as its width, or its length, or perhaps the length/width ratio.
the width is always shorter than the length. other than that, you would require more information about the rectangle (such as the area or the diagonal measurement) to ascertain the width
The width will be 30cm
The diagonal is 26cm
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
The length of the diagonal is about 16.03 feet.
Width is 5.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The diagonal is 20.