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Restate the question: What are the intercepts of the line -4x + y = 8?
To find the y-intercept, let x=0: -4(0)+y=8 <=> y=8
To find the x-intercept, let y=0: -4x+(0)=8 <=> -4x=8 <=> -4x/(-4)=8/(-4) <=> x=-2
With a little practice, and if the numbers are 'nice', you can almost do this by just looking at the equation, or you can think of (0,_),(_,0). My students call this "googly eyes"!
Also note that most texts define an intercept as a number ("the y-intercept is 8"), but it is rare to consider "The y-intercept is (0,8)." to be correct.
18
24
-4
If you mean: y = 4x+2 then the line perpendicular to it will have a slope of -1/4
If you mean y = -4x+1 and (2, 1) then the parallel equation is y = -4x+9
-4x + y = 8At the x-intercept, 'y' is zero.-4x = 8-x = 2x = -2At the y-intercept, 'x' is zero.y = 8
-16
If you mean: y = 4x+2 then 4 is the slope and 2 is the y intercept
8 + y = 4x8 + y - 4x = 4x - 4x 8 + y - 4x = 0 8 - 4x + y = 0
There is no limit to the number of y-intercepts a line can have. The axis itself is a line and it intercepts itself an infinite number of times.
The x intercept is 0.5 and the y intercept is -2.
18
37
4x + 3y = 6y 4x = 3y 4/3 x = y The slope is 4/3 and the y intercept is 0.
y equals 4x+1 is a parallel line to y equals 4x.
4x - 2y = 8 Rearrange into the 'straight line ' form of y = mx + c Hence -2y = -4x + 8 y = 2x - 4 The 'c' value is the y-intercept, which '-4' . The steepness/gradient of the slope is '2'.
The x and y intercepts are where a line on a graph intersects (crosses over) the x or y axis.