Assuming 4x = 5y Then x/y = 5/4
I understand this to be 4x + 3y - 5x + 2y. -x + 5y
If you mean: 4x-5y = -12 and -x+5y =18 Then the solutions of the equations are: x = 2 and y = 4
5y = 4x - 35 Divide each side of the equation by 5 : y = 4/5 x - 7
4x-5y = -8 4x+40 = y => y = 4x+40 Substitute the value of y into the top equation: 4x-5(4x+40) = -8 4x-20x-200 = -8 4x-20x = 200-8 -16x = 192 Divide both sides by -16 to find the value of x: x = -12 Substitute the value of x into the original equations to find the value of y: Therefore: x = -12 and y = -8
4x + 5y = 20 5y = -4x + 20 y = (-4/5)x + 20/5 Now that the equation has been rewritten in standard form, the slope is the cofficient of x, -4/5 [or -0.8]
If: 4x = 5y Then: x = 5y/4
- X + 5Y - 4X + 7 gather terms - X - 4X ( same as - X + (- 4X ) 5Y 7 = - 5X + 5Y + 7 ----------------
First, put the equation in slope-intervcept form y=mx + b 5y=4x + 40 The y intercept is where x=0 so- 5y= 4(0) +40 solve for y y intercept = (0,8) For the x intercept, y=0 0=4x+40 -4x=40 x= -10 xintercept =( -10.0)
Assuming 4x = 5y Then x/y = 5/4
I understand this to be 4x + 3y - 5x + 2y. -x + 5y
If you mean: 4x-5y = -12 and -x+5y =18 Then the solutions of the equations are: x = 2 and y = 4
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
4x-5y=20 x-3y=10 becomes x=3y-10 plug that into the first equation: 4(3y-10)-5y=20 12y-40-5y=20 7y=60 y=60/7 If x=3y-10, then x=3(60/7)-10 x=180/7 - 70/7 x=110/7
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Sounds like somebody's carrying a thing for 'y' . . .Here's something that might work :-4x -5y = 20Add 4x to each side:-5y = 4x + 20Divide each side by -5 :y = -(4/5)x - 4