A triangle.
Assuming that the none of the lines are parallel, they can intersect (pairwise) at three points. Otherwise, the question is tautological.
No, they can intersect at infinitely many points.
Line #1 ==> Y = x Line #2 ==> Y = x + 1 These two lines are parallel, have no points in common, and never intersect. (3 ways to say the same thing)
The lines that pass through points 4 -6 2 -3 and 6 5 3 3 on a grid are the lines y=x.
Yes. A non-convex hexagon with 3 main points like a triangle will only have 3 lines of symmetry.
A triangle? Three lines that intersect in three points.
4
Assuming that the none of the lines are parallel, they can intersect (pairwise) at three points. Otherwise, the question is tautological.
- If you're working on a single sheet of paper (2-D), then you can draw four lines that intersect in 1, 2, 3, 4, 5, or 6 points. - If in 3-D space, then you can also draw four lines that don't intersect at all.
From a rough sketch they appear to be parallel lines but for a more accurate answer plot the points on the Cartesian plane
There is an infinite number of lines.
it's impossible if the line is straight but if u can make it zig-zag then you can make them intersect at as many points as you like.
Concurrent lines
No, they can intersect at infinitely many points.
3Num3
28 points. Each added line n intersects (n-1) other lines. 7 + 6 + 5 + 4 + 3 + 2 +1 = 28 The formula is P = n(n-1)/2, which here is 8x7/2 = 28 It is possible to have any number of points between 28 and 1 if multiple lines intersect at the same point.
Line #1 ==> Y = x Line #2 ==> Y = x + 1 These two lines are parallel, have no points in common, and never intersect. (3 ways to say the same thing)