Assuming that the none of the lines are parallel, they can intersect (pairwise) at three points. Otherwise, the question is tautological.
No, they can intersect at infinitely many points.
Line #1 ==> Y = x Line #2 ==> Y = x + 1 These two lines are parallel, have no points in common, and never intersect. (3 ways to say the same thing)
The lines that pass through points 4 -6 2 -3 and 6 5 3 3 on a grid are the lines y=x.
Yes. A non-convex hexagon with 3 main points like a triangle will only have 3 lines of symmetry.
A triangle? Three lines that intersect in three points.
4
Assuming that the none of the lines are parallel, they can intersect (pairwise) at three points. Otherwise, the question is tautological.
- If you're working on a single sheet of paper (2-D), then you can draw four lines that intersect in 1, 2, 3, 4, 5, or 6 points. - If in 3-D space, then you can also draw four lines that don't intersect at all.
From a rough sketch they appear to be parallel lines but for a more accurate answer plot the points on the Cartesian plane
it's impossible if the line is straight but if u can make it zig-zag then you can make them intersect at as many points as you like.
There is an infinite number of lines.
Concurrent lines
No, they can intersect at infinitely many points.
28 points. Each added line n intersects (n-1) other lines. 7 + 6 + 5 + 4 + 3 + 2 +1 = 28 The formula is P = n(n-1)/2, which here is 8x7/2 = 28 It is possible to have any number of points between 28 and 1 if multiple lines intersect at the same point.
Line #1 ==> Y = x Line #2 ==> Y = x + 1 These two lines are parallel, have no points in common, and never intersect. (3 ways to say the same thing)
3Num3