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How many common points for intersection of four lines?
- If you're working on a single sheet of paper (2-D), then you can draw four lines that intersect in 1, 2, 3, 4, 5, or 6 points. - If in 3-D space, then you can also draw four lines that don't intersect at all.
What is the greatest number of intersection points in four coplanar lines can have?
The greatest number of intersection points that four coplanar lines can have occurs when no two lines are parallel and no three lines intersect at the same point. In this case, the maximum number of intersection points can be calculated using the formula ( \frac{n(n-1)}{2} ), where ( n ) is the number of lines. For four lines, this results in ( \frac{4(4-1)}{2} = 6 ) intersection points.
What is the maximum number of points of intersection when two circles and five straight lines intersect each other?
When two circles intersect, they can create a maximum of 2 intersection points. Each straight line can intersect with each of the two circles at a maximum of 2 points, contributing 10 points from the lines and circles. Additionally, the five straight lines can intersect each other, yielding a maximum of ( \binom{5}{2} = 10 ) intersection points. Therefore, the total maximum points of intersection are ( 2 + 10 + 10 = 22 ).
What is the number of points equidistant from two intersecting lines and 2 centimeters from the point of intersection?
2
What is the greatest possible number of points of intersection for 100 lines?
100*99/2 = 4950
How many common points for intersection of four lines?
- If you're working on a single sheet of paper (2-D), then you can draw four lines that intersect in 1, 2, 3, 4, 5, or 6 points. - If in 3-D space, then you can also draw four lines that don't intersect at all.
Can 2 circle and 3 lines get 17 intersection points?
Yes. Draw three line segments so that they cross at three points forming a triangle (with each side extending beyond the vertices of the triangle). Draw one circle to enclose the triangle without touching it to intersect the extended sides at a further 6 points, making 9 points of intersection so far. Draw the second circle slightly shifted (relative to the first) so that it also encloses the triangle (without touching it) creating a further 6 intersection points with the three lines and 2 with the first circle; an additional 8 intersection points making 17 in all.
What is the greatest number of intersection points in four coplanar lines can have?
The greatest number of intersection points that four coplanar lines can have occurs when no two lines are parallel and no three lines intersect at the same point. In this case, the maximum number of intersection points can be calculated using the formula ( \frac{n(n-1)}{2} ), where ( n ) is the number of lines. For four lines, this results in ( \frac{4(4-1)}{2} = 6 ) intersection points.
What is the maximum number of points of intersection when two circles and five straight lines intersect each other?
When two circles intersect, they can create a maximum of 2 intersection points. Each straight line can intersect with each of the two circles at a maximum of 2 points, contributing 10 points from the lines and circles. Additionally, the five straight lines can intersect each other, yielding a maximum of ( \binom{5}{2} = 10 ) intersection points. Therefore, the total maximum points of intersection are ( 2 + 10 + 10 = 22 ).
What is the number of points equidistant from two intersecting lines and 2 centimeters from the point of intersection?
2
What is the greatest possible number of points of intersection for 100 lines?
100*99/2 = 4950
How do you verify that a triangle is isosceles?
The step to verify an isosceles triangle is: 1) Find the intersection points of the lines. 2) Find the distance for each intersection points. 3) If 2 of the distance are the same then it is an isosceles triangle.
What are the possible intersections of more than two lines?
For n lines there are n*(n-1)/2 possible intersection points.
How many points do 5 intersecting lines have?
Five intersecting lines can have a maximum of 10 points of intersection, assuming that no two lines are parallel and no three lines intersect at the same point. Each pair of lines can intersect at one unique point, and the number of ways to choose 2 lines from 5 is given by the combination formula ( \binom{5}{2} = 10 ). Therefore, with optimal conditions, the maximum number of intersection points is 10.
What is the maximum number of points in which 4 lines can intersect?
The maximum number of intersection points formed by 4 lines occurs when no two lines are parallel and no three lines are concurrent (i.e., they do not all meet at a single point). In this case, each pair of lines can intersect at a unique point. The number of ways to choose 2 lines from 4 is given by the combination formula ( \binom{n}{2} ), so for 4 lines, the maximum number of intersection points is ( \binom{4}{2} = 6 ).
What is the greatest number of points of intersection that can occur when 2 different circles and 2 different straight lines are drawn on the same piece of paper?
please answer
A point where 2 lines meet?
An intersection.
