Two ends make 8, so two sides must make 34 - 8 = 26, so each side is 13, which is the length.
If the given dimensions are that of a rectangle then perimeter is: 34 feet
The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.
The dimensions of the rectangle are 2 units and 15 units
11 ft. 11+11+6+6=34
No.For example, a 1 metre * 72 metre rectangle and a 8 metre * 9 metre rectangle both have areas of 72 square metres. But the perimeter of the first is 146 metres while that of the second is 34 metres.
If the given dimensions are that of a rectangle then perimeter is: 34 feet
If the perimeter is 34 feet, and two of the sides are 4 ft. each (a total of 8 feet), then the other two sides are a total of 26 feet (34-8), or 13 feet each. So the rectangle is 13 feet long and 4 feet wide.
The maximum area for a rectangle of fixed perimeter is that of the square that can be formed with the given perimeter. 136/4 = 34, so that the side of such a square will be 34 and its area 342 = 1156.
length = 34 and width = 3 Perimeter = 34+34+3+3 = 74 Area = 34*3 = 102
The dimensions of the rectangle are 2 units and 15 units
Perimeter of rectangle = 2 x ( L + W ) = 2 x 64 = 128 cm. or Perimeter of rectangle = 2L + 2W = 68 + 60 = 128 cm.
Very hard question, It took me one hour to solve it. I think it is 0.12 m or 120 mm.
If it's a 12 by 5 rectangle then the perimeter is: 12+5+12+5 = 34 cm
5 x 12
34 feet
By Pythagoras, the other side is 24 inches long. So the perimeter is 2*(10+24) = 2*34 = 68 inches.
The dimensions of the rectangle are 3 inches by 14 inches