V*(V-1)/2
If you add the vertices and Faces and subtract 2 from that number you get the number of edges. Vertices+Faces=Edges+2
A sphere- there are no faces, edges or vertices
It has 7 faces, 15 edges and 10 vertices
5 vertices and 8 edges.5 vertices and 8 edges.5 vertices and 8 edges.5 vertices and 8 edges.
Oh, isn't that a happy little question! Let's think about it together. A prism has 2 bases and the same number of edges as the number of sides on those bases, plus the number of edges connecting the corresponding vertices on the bases. So, a prism can't have seven more edges than vertices because the number of edges is determined by the number of sides on the bases and the number of vertices.
n * (n - 1) / 2 That would ignore the "acyclic" part of the question. An acyclic graph with the maximum number of edges is a tree. The correct answer is n-1 edges.
It is a true statement.
n - 1
n-1
I believe that such an object cannot exist in normal 3-d space. If there are 6 vertices, the maximum number of edges is 12.
no numbers have the same number of edges and vertices
If you add the vertices and Faces and subtract 2 from that number you get the number of edges. Vertices+Faces=Edges+2
A sphere- there are no faces, edges or vertices
for any prism , number of ___ + number of vertices = number of edges + ___
There is no limit to the number of vertices nor edges.
Edges: 4, Vertices: 4 and Edges: still 4, their number hasn't changed!
Let G be a complete graph with n vertices. Consider the case where n=2. With only 2 vertices it is clear that there will only be one edge. Now add one more vertex to get n = 3. We must now add edges between the two old vertices and the new one for a total of 3 vertices. We see that adding a vertex to a graph with n vertices gives us n more edges. We get the following sequence Edges on a graph with n vertices: 0+1+2+3+4+5+...+n-1. Adding this to itself and dividing by two yields the following formula for the number of edges on a complete graph with n vertices: n(n-1)/2.