Besides the shadow, you also need the angle of elevation. Then the height can be found .
Use Pythagoras, h^(2) = top^(2) + shadow^(2) Substituting h^(2) = 18^(2) + 24^(2) h^(2) = 324 + 576 h^(2) = 900 Square root BOTH sides. h = 30 ft. So an imaginary line from the top of the flag pole to the tip of the shadow is 30 feet.
It is 90 feet in height
The flagpole is 26 feet, 3 inches tall. (210/8 feet = 26.25 feet)Since the ratio of height to shadow is 6/8, the flagpole is also 3/4 as tall as its shadow.6/8 (man) = x/35 (pole)6/8 (35) = x210/8 = xx = 26.25 feet
Use Tangent(Tan) function Tan( 26) = opposite(tall( / Adjacent(shadow) Tan(26) = opposite(tall) / 82 feet Algebraically rearrange opposite(tall) = 82feet*Tan(26) NB Do NOT write as ' Tan(26)82ft ' , as it confuses the numbers under the Tan function. Hence Height = 82ft * 0.4877326886.... Height = 39.9940... ft ~ 40 feet.
The sunlight's vertical angle to the man (standing straight) and to the totem pole is the same. Therefore the length of their shadows (one side of a right triangle) to their heights (the other side) will have the same ratio.Man is 74 inches tall, shadow is 4 feet.Totem Pole is X inches tall, shadow is 6 feet (1.5 times as long)74 inches x 1.5 = 111 inches, the height of the totem pole (9' 3" tall).
We can solve this problem using a ratio. Since a 6 foot man casts a 4 foot shadow we can write this ratio as 6:4. If we reduce this ratio we get 3:2. Now we're stating that for every 3 feet of height, the shadow cast will be 2 feet.Now we can work our problem out using a small table:3 feet of flag pole = 2 feet of shadow6 feet of flag pole = 4 feet of shadow9 feet of flag pole = 6 feet of shadow12 feet of flag pole = 8 feet of shadow15 feet of flag pole = 10 feet of shadow18 feet of flag pole = 12 feet of shadowTherefore an 18 foot flag pole will cast a 12 foot shadow at the same time that a 6 foot man casts a 4 foot shadow.
6 feet
Use Pythagoras, h^(2) = top^(2) + shadow^(2) Substituting h^(2) = 18^(2) + 24^(2) h^(2) = 324 + 576 h^(2) = 900 Square root BOTH sides. h = 30 ft. So an imaginary line from the top of the flag pole to the tip of the shadow is 30 feet.
It depends exactly how long the shadow of the pole is... multiply whatever it is by 36/15 to get the answer.
25 feet tall
The ratio of the height of the object to its shadow are the same for both objects. So, if H is the height of the tower, then H/500 = 40/36 therefore H = 500*40/36 = 555.55... feet.
2
The tree is 25 feet tall. A 5 foot pole cast a 2 foot shadow. This means that the sun angle causes the shadow to be 2/5 the length of the object casting it. The tree's shadow is 10 feet tall. Multiply 10 feet by 5/2 (inverting the fraction because we're going the other way) and we get 25 feet.
It is 90 feet in height
The flagpole is 26 feet, 3 inches tall. (210/8 feet = 26.25 feet)Since the ratio of height to shadow is 6/8, the flagpole is also 3/4 as tall as its shadow.6/8 (man) = x/35 (pole)6/8 (35) = x210/8 = xx = 26.25 feet
Use Tangent(Tan) function Tan( 26) = opposite(tall( / Adjacent(shadow) Tan(26) = opposite(tall) / 82 feet Algebraically rearrange opposite(tall) = 82feet*Tan(26) NB Do NOT write as ' Tan(26)82ft ' , as it confuses the numbers under the Tan function. Hence Height = 82ft * 0.4877326886.... Height = 39.9940... ft ~ 40 feet.
15 feet high