AC is in the range (2x - 10, 14x + 4)
30
14
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
27
8
AC is in the range (2x - 10, 14x + 4)
74
5
ind the area of the rhombus if AE = 20 m and DE = 32 m.
30
24;
14
First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31
this is what you would: 4x+6=3x-1 -6 -6 ---- 4x=3x-7 -3x -3x ---- 1x=-7 ---- x=-7
If AE would start making everyone Mem forever with unlimitted AC's, AE wouldn't have the Money to make the Releases and adventually there games including AQWorlds would shutdown.
If we put 2x - 3y = 12 into y = mx + b format, you will get.. y = 2/3x - 4 Therefore the intercepts would be... y= -4 x= 6