5
74
associative property
between A and B
Difficult to tell when you cannot use parentheses. a*(b+c) or a(b+c) = ab + ac This is known as the distributive property of multiplication over addition.
If AC plus CB equals AB and AC is equal to CB, then point C is the midpoint of segment AB. This means that point C divides the segment AB into two equal parts, making AC equal to CB. Therefore, point C is located exactly halfway between points A and B.
74
AC is in the range (2x - 10, 14x + 4)
yes because ab plus bc is ac
the midpoint of AB.
If: y = x^2 -4x +8 and y = 8x -x^2 -14 Then: x^2 -4x+8 = 8x -x^2 -14 Transposing terms: 2x^2 -12x+22 = 0 Divide all terms by 2: x^2 -6x +11 = 0 Using the discriminant b^2 -4(ac): 36 -4(1*11) = -8 Therefore it follows that there are no points of intersection because the discriminant is less than zero.
associative? single replacement
associative property
Are you sure that the given expressions are right? Because we are dealing with complex numbers (a little bit work for this kind of exercise).ab = 4x + 8bc = 8x + 4ac = 18x - 11b = a/(4x + 8)c = b/(8x + 4) = [a/(4x + 8)[/(8x + 4) = a/[(4x + 8)(8x + 4)]c = a/(18x - 11)a/[(4x + 8)(8x + 4)] = a/(18x - 11) this happens only when:(4x + 8)(8x + 4) = (18x - 11)32x^2 + 16x + 64x + 32 = 18x - 1132x^2 + 62x + 43 = 0x = [-62 ± √(62^2 - (4)(32)(43)]/[(2)(32)]x = [-62 ± √(-1660)]/64x = [-62 ± i√(1660)]/64x = -62/64 ± i√(1660/4096) (64^2 = 4096)x = -31/32 ± i√[415/1024]Substitute -31/32 ± i√[415/1024] for x, and find the value of ab, bc, and ac.ab = 4x + 8bc = 8x + 4ac = 18x - 11
between A and B
if f :- a+b = ac then fd:- a.b = a+c
Difficult to tell when you cannot use parentheses. a*(b+c) or a(b+c) = ab + ac This is known as the distributive property of multiplication over addition.
This is a 'Sngle Displacement' reaction ( A + BC --> AC + B