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If AE 8x- 3 and EC 6x plus 7 then AC?

Updated: 10/31/2022
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AC is in the range (2x - 10, 14x + 4)

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Q: If AE 8x- 3 and EC 6x plus 7 then AC?
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If AC equals 22 and AE equals 2x - 5 what is x?

8


The diagonals of square abcd intersect at e if ae equals 2 find to perimeter of abcd?

First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31


If ABCD is a rectangle and AE equals 15 what is the length of DB?

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If abce is an isosceles trapezoid and acde is a rectangle what is the length of ae when ab equals 10 and ec equals 20?

Draw the isosceles trapezoid ABCE, where the length of the bases AB (on the top) and EC are respectively 10 and 20. From A and B draw the perpendiculars to the base EC of the trapezoid, and label the point of intersections with F and G). The rectangle ABGF is formed, where the length of FG is 10 (since the two opposite sides of a rectangle are congruent). Then the lengths of EF and GC are 5 (since the trapezoid is isosceles). Draw the diagonal AC. From C and E draw the parallel lines respectively to AE and AC, and label the intersection point with D. So the rectangle ACDE is formed. Thus, the triangle EAC is a right triangle, where the angle A is 90 degrees (as the angle of a rectangle), and AF is the altitude drawn at the hypotenuse EC. We have a theorem that states: "If an altitude is drawn to the hypotenuse of a right triangle, then each leg is the geometric mean between the hypotenuse and its touching segment on the hypotenuse". So we have, EC/AE = AE/EF, which yields AE2 = EC*EF, and so AE = √(20*5) = 10. or using the same diagram, Since the diagonals of a rectangle bisect each other (let's say they bisect at H), then AH is the median of the right triangle EAC, drawn to the hypotenuse EC, so its length is the half of the hypotenuse. So the length of AH is 10. Since the trapezoid is isosceles, then the diagonal BE also will form a right triangle EBC, where the median BH also it is 10. So the triangle ABH is equilateral, where angle A is 60 degrees, and it is congruent with angle H of the triangle AHE, as two alternate interior angles. Thus, the isosceles triangle AHE is also equilateral, where AE = 10.


If ABCD is a rectangle and AE 15 what is the length of?

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Related questions

If AE equals 8x-3 and 6x plus 7 then AC equals?

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If AE equals 8x - 3 and EC equals 6x plus 7 then AC equals?

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Given ABCD equals 38 and equals 3x plus 4 find the value of x?

ANSWER 5 EXPLANATION The diagonals bisect each other so, AE=CE This implies that 3x+4+3x+4=38 6x+8=38 Group similar terms 6x=38-8 6x=30 x=5


If AC equals 22 and AE equals 2x - 5 what is x?

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Given ABCD AC 22 and AE 2x-5 find the value of x?

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How do you solve this. in parallelogram abcd diagonals ac and bd intersect at e if ac 4x plus 6 and ae equals 3x minus 1 find the value of x?

this is what you would: 4x+6=3x-1 -6 -6 ---- 4x=3x-7 -3x -3x ---- 1x=-7 ---- x=-7


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How can a Given abcd ac 28 and ae 3x - 7 find the value of x?

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What is Ae on the periodic table?

I personally don't think there is an Ae on the periodic table. There is Am and an At though. The following are the elements on the periodic table with abbreviations beginning with an A: Al - Aluminium Ar - Argon As - Arsenic Ag - Silver Au - Gold At - Astatine Ac - Actinium Am - Americium


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The diagonals of square abcd intersect at e if ae equals 2 find to perimeter of abcd?

First of all we work out the length of a sides ab, bc, CD, & ad. We know that ab = bc = CD = ad also ae = ac/2 If a to e = 2 then ac = 4 so ab2 + bc2 = ac2 2ab2 = 16 ab2 = 8 ab = 2.8284271247461900976033774484194 so the perimeter = ab * 4 = 11.31


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