The answer is 22.
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Here's how to convert dB units (with usually a 1 Watt or whatever 1 value as reference) to dBm units (with a 1 miliWatt reference value):x= value to be convertedx [dB]= x + 30 [dBm]Proof:P= 1 Watt--> 10*log10(1)= 0 [dB] (this is 1 Watt in dB)--> 10*log10(1/(1*10^(-3)))= 10*log(1*10^3)= 30 dBm (this is 1 Watt to dBm)Now, if you do whatever number of examples you want to do, you'll end up in concluding the conversion dB to dBm is totally linear without of actually having to proof the linear properties. (i'm too lazy to write it here).Hope this helps....Regards,STMI
If two chords intersect inside a circle, the acute angle they form is one half of the sum of the arcs intercepted by its sides and by the vertical angle SO... The acute angle will be one half the sum of the two arcs. So it is 1/2(42+94)=68 degrees.
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24;
"3 dB" is a nickname for "1/2 power". "1/2 power" in dB = 10 log(1/2) = 10 (-0.30103) = -3.01 dB
AnswerYou are going to have to write out your algebra problems more accurately than that if someone is going to help you. The two statement don't make sense.It sounds like my son's geometry problem on angle additions and segment addition, except his reads if ED = x + 4 and DB = 3x-8 then EB is 20; DB is 10 and ED = 10 and x is 6..
No, it is 10 times louder. dB is a logarithmic scale; every 10 dB, the intensity increases by a factor of 10. Thus, 10 dB is 10 times louder than 0 dB, 20 dB is 10 times louder than 10 dB, and 30 dB is 10 times louder than 20 dB.No, it is 10 times louder. dB is a logarithmic scale; every 10 dB, the intensity increases by a factor of 10. Thus, 10 dB is 10 times louder than 0 dB, 20 dB is 10 times louder than 10 dB, and 30 dB is 10 times louder than 20 dB.No, it is 10 times louder. dB is a logarithmic scale; every 10 dB, the intensity increases by a factor of 10. Thus, 10 dB is 10 times louder than 0 dB, 20 dB is 10 times louder than 10 dB, and 30 dB is 10 times louder than 20 dB.No, it is 10 times louder. dB is a logarithmic scale; every 10 dB, the intensity increases by a factor of 10. Thus, 10 dB is 10 times louder than 0 dB, 20 dB is 10 times louder than 10 dB, and 30 dB is 10 times louder than 20 dB.
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There are several types of dB. dB SPL are decibels measuring sound pressure levels. There is an accepted reference point of 0 dB SPL which equals 20 micropascals = 2 × 10-5 pascals. dB SL are decibels measuring a signal relative to an individuals auditory threshold. For example, if a person's minimum threshold is 30 dB HL (yet another type of decibel measuring how much worse a person's hearing is based on a referential dB level) and a signal is at 40 dB HL, the sensation level of this signal to this individual is 10 db SL (40 dB - 30 dB = 10 dB SL).
dB (decibel) is a logarithmic measure of the ratio of two power values, for example, two signal strengths. This is often used for power gain or power loss. For example, a loss of 10 dB means that the signal degrades by a factor of 10, a loss of 20 dB means that the signal degrades by a factor of 100, and a loss of 30 dB means that the signal degrades by a factor of 1000.
The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.The decibel (dB) scale is logarithmic. An increase of power by a factor of 10 is an increase of +10 dB. If power increases by a factor of 100, that is equivalent to +20 dB.
A factor of 100. Every 10 dB, the intensity increases by a factor of 10.A factor of 100. Every 10 dB, the intensity increases by a factor of 10.A factor of 100. Every 10 dB, the intensity increases by a factor of 10.A factor of 100. Every 10 dB, the intensity increases by a factor of 10.
Two ways to do it. In this particular problem, it's a matter of opinionwhich one is easier and which one is harder.Way #1:Convert dBm to watts, multiply by gains, convert output watts to dBm.+20 dBm = 0.1 watt.Output power = (0.1 watt) x (ap1) x (ap2) x (ap3) = 0.1 x 10 x 4 x 23 = 92 watts = +49.64 dBmWay #2:Convert each gain ratio to dB, then add all dB to input power.ap1 = 10 = 10 dBap2 = 4 = 6.02 dBap3 = 23 = 13.62 dB+20 dBm + 10dB + 6.02 dB + 13.62 dB = +49.64 dBm
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