use the formula y-y1=m(x-x1)
If you mean: (y2-y1)/(x2-x1) and (y1-y2)/(x1-x2) then either works out the same.
Given two coordinates (x1,y1) and (x2,y2) The midpoint is ( ((x2+x1)/2) , ((y2+y1)/2) )
A statement that two ratios are equal is called a proportion in math. An example of a proportion is 1/2 equals 2/4. In this proportion, if you cross multiply, you find that 4 x1 is equal to 2 x 2, which is a true statement or proportion.
midpoint=(X1 + X2, Y1 + Y2)divide both of those by 2.X1 + X2 divided by 2 should give you the co ordinate for X.
it equals x1 it equals x1
The component form of a vector AB would typically be represented as (x2 - x1, y2 - y1), where A is at the point (x1, y1) and B is at the point (x2, y2).
3
i think its pretty much the same thing because matrix X1 X2 IS ACTUALLY X1 X2
If point a has coordinates (x1,y1), and point b has coordinates (x2, y2), then the slope of the line is given by the formula: m = (y2-y1)/(x2-x1).
A={(6,5),(5,6)} And The probability P(A) equals1/8
X or if it says what "x" equals then plug that in and multiply
X1 = -81
AB = sqrt (x2 - x1)2 + (y2 -y1)2 Sqrt is the square root of
It's m = y2 - y1/ x2- x1 It's m equals y2 minus y1 over x2 minus x1
If A = (x1, y1) and B = (x2, y2) then, if x1 ≠x2 the slope of AB is (y2 - y1)/(x2 - x1) There are various ways of interpreting slope > 0. One way is that it implies that y2 > y1 and x2 > x1 or y2 < y1 and x2 < x1 that is both the coordinates of one point are greater than both the coordinates of the other point. Note that if x1 = x2 then the slope is not defined.
AB can be found by using the distance formula, which is the square root of (x2-x1)^2 + (y2-y1)^2. In this case, AB= the square root of (-2-(-8))^2 + (-4-(-4))^2 which AB= the square root of 64 + 0 which AB=8.