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What happens to the area of a rectangle when both dimensions are doubled?
It would be 4 times greater.To find this algebraically: let L be the length and W the width originallyA = L x WWhen both are doubled, the equation becomesA = (2L) x (2W) = 4LWThe area of the rectangle is quadrupled if both the length and width are doubled.
Formula for finding the area of a rectangle?
A = lw Area of a rectangle = length times width
What is the effect on the perimeter of a rectangle if the dimension are doubled what is the effect on its area?
Let's take a look at this problem.Rectangle Perimeter = 2(l + w)Rectangle Perimeter =? 2(2l + 2w)Rectangle Perimeter =? (2)(2)(l + w)2(Rectangle Perimeter) = 2[2(l + w)]Thus, we can say that the perimeter of a rectangle is doubled when its dimensions are doubled.Rectangle Area = lwRectangle Area =? (2l)(2w)Rectangle Area =? 4lw4(Rectangle Area) = 4lwThus, we can say that the area of a rectangle is quadruplicated when its dimensions are doubled.
The length of a rectangle is twice its width If the perimeter of the rectangle is 54y find its area?
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
What is the area of a rectangle that has a length of 38 and a width of 28?
Length times width gives the area of a rectangle. The rectangle with a length of 38 and a width of 28 has an area of 1064 square units.
