If two consecutive sides of a rhombus are represented by 3x - 6 and x plus 14 then the perimeter of the rhombus is what?

Answer 1

To find the perimeter of a rhombus, you need to add up the lengths of all four sides. In a rhombus, all four sides are congruent. Given that two consecutive sides are represented by 3x - 6 and x + 14, we can set up an equation: 3x - 6 = x + 14. Solving for x gives x = 10. Substituting x back into the expressions gives the side lengths as 24 and 24. Therefore, the perimeter is 4 times the length of one side, which is 4 * 24 = 96 units.

Answer 2

Oh, what a happy little rhombus we have here! To find the perimeter, we simply add up all the sides. Since a rhombus has four equal sides, we can multiply one side by 4. So, the perimeter would be (3x - 6) + (3x - 6) + (x + 14) + (x + 14), which simplifies to 8x + 16.

Answer 3

Oh, dude, to find the perimeter of a rhombus, you just add up all the sides. So, if two consecutive sides are 3x - 6 and x + 14, you'd have to double each to account for all four sides. Then you just add them together and voilà, you've got the perimeter. Easy peasy!

Answer 4

Answer:

96

Step-by-step explanation:

we know that in a rhombus all the sides are equal so,

x+14 = 3x - 6

=> 2x = 20

=> x = 10

so putting x in (x+14)

we get the side is equal to 24

perimeter = 4*(side)

= 4*24

=96

Answer 5

96

Answer 6

Answer is 96