The polygon is a Quadrilateral.
It is 5.6
If at least one vertex of the inner triangle lies on the side of the outer triangle then yes, it is a complex polygon. However, if none of the vertices of the inner triangle are on the sides of the outer triangle then there are two disjoint triangles and that does not represent a polygon.
A subset is smaller. A subset is made up of entries from the regular set, so it cannot be bigger, and it cannot be the same size, because that would just be the regular set again. Example: {2, 3, 5} is a subset of {2, 3, 4, 5, 6}
To find the area, first divide the shape into regular, simple shapes. Then use formulas to find the area of the smaller, regular shapes. Lastly, add up all the smaller areas to find the area of the original shape.
To find the area, first divide the shape into regular, simple shapes. Then use formulas to find the area of the smaller, regular shapes. Lastly, add up all the smaller areas to find the area of the original shape.
The diagonals (drawn from a point) help in dividing the regular polygon into smaller triangles. The sum of the areas of these smaller triangles help in determining the total area of the polygon.
The circle has a smaller area than the polygon.
No because as the polygon gets smaller the angles and sides get biggerso they can't tessellate by themselves.
To find the area, first divide the shape into regular, simple shapes. Then use formulas to find the area of the smaller, regular shapes. Lastly, add up all the smaller areas to find the area of the original shape.
An equilateral triangle is the only polygon in which the exterior angle is larger than the interior angle. They are equal in a square and smaller in all regular polygons with more sides,
A regular polygon cannot have internal angles smaller than 60 degrees. If each EXTERNAL angle is 40 degrees, the triangle has 360/40 = 9 sides.
It depends on whether the ratio applies to the areas or to the lengths of the sides.
The measure of the interior angle of a regular polygon is: theta = (n - 2) * 180 / n. So for our case, we have: 47 = (n - 2) * 180 / n. 47n = 180n - 360 -133n = -360 n = 360/133 As 360/133 is not an integer, we conclude that there is no regular polygon with interior angle 47. OR, if you prefer to learn graphically, consider that a triangle is the polygon with the fewest number of sides. As you increase the number of sides of a regular polygon, you increase the interior angle. Thus since the interior angle of a regular triangle is 60 degrees. Thus, in order to get an angle smaller than 60 degrees, we would need to have fewer sides than a triangle - which isn't possible.
No, because successive discounts are taken on the discounted price after the first of the successive discounts. Therefore, 3 successive 5 % discounts will total to a smaller discount than one 15 % discount.
No. In a convex polygon, all the internal angles are smaller than 180 degrees.
5mx10m
Yes. In the regular polygon, the angles are all equal parts of the 1,080 . In the irregular one, there are bigger and smaller interior angles, but they still add up to the same total.