Yes, the three given lengths will form a triangle.
Three lengths can make a triangle if, and only if, the sum of the two shorter lengths is greater than the longest length.
The two shorter lengths are 56 ft and 16 ft with a sum of 56 ft + 16 ft = 72 ft
72 ft is greater than 65 ft so 56 ft, 65 ft and 16 ft will make a triangle.
Multiply the base times the height and divide by 2. (16x7)/2=56 square feet.
yes
A square has all four sides of the same length Thus perimeter_square = 4 × side_length Each side is of length 4x ft, thus: 4 × (4x ft) = 56 ft → 16x ft = 56 ft → x = 56 ÷ 16 ft = 3½ ft = 3.5 ft
I assume you want the area of a triangle with side lengths 18 ft, 22 ft and 16 ft. Given the sides of a triangle, its area is given by: area = √(s(s - a)(s - b)(s - c)) Where s is the semi-perimeter, ie s = ½(a + b + c) or triangle with sides 18 ft, 22 ft 16 ft, area is: s = ½(18 + 22 + 16) ft = 28 ft → area = √(28(28 - 18)(28 - 22)(28 - 16)) ft² = √3360 ft² ≈ 57.97 ft²
65 1/2 pieces
The ratio of the length of the side of a right angle triangle must be 3,4,5 16,56,65 are not in that ratio.
Multiply the base times the height and divide by 2. (16x7)/2=56 square feet.
yes
No because the given dimensions do not comply with Pythagoras' theorem for a right angle triangle
A square has all four sides of the same length Thus perimeter_square = 4 × side_length Each side is of length 4x ft, thus: 4 × (4x ft) = 56 ft → 16x ft = 56 ft → x = 56 ÷ 16 ft = 3½ ft = 3.5 ft
I assume you want the area of a triangle with side lengths 18 ft, 22 ft and 16 ft. Given the sides of a triangle, its area is given by: area = √(s(s - a)(s - b)(s - c)) Where s is the semi-perimeter, ie s = ½(a + b + c) or triangle with sides 18 ft, 22 ft 16 ft, area is: s = ½(18 + 22 + 16) ft = 28 ft → area = √(28(28 - 18)(28 - 22)(28 - 16)) ft² = √3360 ft² ≈ 57.97 ft²
65 1/2 pieces
distance_to_other_side = width_of_lot - (width_of_house + distance_of_house_from_side) = 56 ft 9 in - (34 ft 10 in + 5 ft 5 in) = 56 ft 9 in - 40 ft 3 in = 16 ft 6 in
The area of a triangle is one half base times height. 1/2 b h = 120 1/2 130 h = 120 65 h = 120 h = 120/65 h = 1.85
the length of the base would be 16
256 sq in = 1.7777 sq ft ea X 56 tiles = 115.55 sq ft area to cover
Area = 1/2*b*h Area = 1/2(16 ft)(0.7 ft) = 5.6 ft2 ==============funny looking triangle