Average = (7 + 14 + 12) / 3Average = 33 / 3 = 11
7 X 2 = 14 6 X 2 = 12 12 + 14 = 26 ----
12=)Improved Answer:-It has 14 because the formula of 0.5*(49-27) = 14 diagonals
From the Pythagorean Theorem: c^2 = a^2 + b^2. So,c = √(a^2 + b^2) substitute the given values:c = √(4^2 + 3^2)c = √(16 + 9)c = √25c = 5 (since the length is always positive)One of the Pythagorean triples is 3,4,5. So, if you know all the Pythagorean triples, you don't need to do the computations above.The Pythagorean triple: A set of three positive integers a, b, and c such that a^2 + b^2 = c^2. Pythagorean triples that have greatest common divisor equal to 1 include the following: {3, 4, 5}, {5,12, 13}, {8, 15, 17}, {7, 24, 25}, and {20, 21, 29}.
There are more than four, but so I'll give you the ones that I know: 3-4-5. 5-12-13. 8-15-17, 7-24-25. 12-35-37, and 9-40-41. Multiples of these triplets work as well.
No.
There are infinitely many combinations. Using any pair of integers m and n such that m > n > 0, the integers m2 - n2, 2mn and m2 + n2 will form a Pythagorean triple.
Average = (7 + 14 + 12) / 3Average = 33 / 3 = 11
To find six over seven of 14, you first calculate six over seven, which is 6/7. Then, you multiply 6/7 by 14. This can be done by multiplying the numerators (6 x 14) to get 84, and the denominators (7 x 1) to get 7. Therefore, six over seven of 14 is equal to 84/7, which simplifies to 12.
A Pythagorean triple is a group of three whole number which can be the sides of a right angled triangle, eg: (3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17), (9, 40, 41), (11, 60, 61), (12, 35, 37), (13, 84, 85), (16, 63, 65), (20, 21, 29), (28, 45, 53), (33, 56, 65), (36, 77, 85), (39, 80, 89), (48, 55, 73), (65, 72, 97)
6 13 2 12 7 14 3
It is: 14/12 = 7/6
lcm(7, 12, 14) = 84 Using prime factorization: 7 = 7 12 = 2² x 3 14 = 2 x 7 lcm = 2² x 3 x 7 = 84
Yes, 12/14 can be reduced to 6/7
7
12-11+5*23*3*14+14/11-7 1)5*23*3*14=4830 12-11+4830+14/11-7 2)14/11=1.27 12-11+4830+1.27-7= 1+4830+8.27 4839.27
13/13 + 12/14 = 13/7 or 16/7