No.
7*7 = 49
12*12 = 144
14*14 = 196
49 + 144 = 193, which does not equal 196
Average = (7 + 14 + 12) / 3Average = 33 / 3 = 11
7 X 2 = 14 6 X 2 = 12 12 + 14 = 26 ----
12=)Improved Answer:-It has 14 because the formula of 0.5*(49-27) = 14 diagonals
12
There are more than four, but so I'll give you the ones that I know: 3-4-5. 5-12-13. 8-15-17, 7-24-25. 12-35-37, and 9-40-41. Multiples of these triplets work as well.
No.
The combination 5, 12 and 13 is a Pythagorean triple.
7
There are probably tens of such sets. Some are: 5, 6, 7, 7, 8, 11, 13, 14, 15, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 16, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 15, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 15, 17, 18 5, 6, 7, 7, 7, 12, 12, 14, 15, 16, 16, 18 5, 6, 7, 7, 7, 12, 12, 14, 14, 16, 16, 18
There are infinitely many combinations. Using any pair of integers m and n such that m > n > 0, the integers m2 - n2, 2mn and m2 + n2 will form a Pythagorean triple.
Good old Arthur. There is a Pythagorean triple (5-12-13) lurking in this question. Diagonal is 26 cm making x = 7
12/14 in its simplest form is 6/7
6/7 = 12/141/2 = 7/14(6/7) - (1/2) = (12/14) - (7/14) = 5/14
Average = (7 + 14 + 12) / 3Average = 33 / 3 = 11
7
6 13 2 12 7 14 3
What is 6 / 20 * 7 / 14 * 12 / 21 equals