Aww, man. Proofs? You're on your own.
A=1/2bh The area of a triangle is 1/2bh. If the base of it is a triangle and all 4 of the triangles aren't the same, then you have to find the area of the base triangle and then the three other triangles (which should all have the same area). If all four of the triangles have the same area, then just find the area of one of the triangles and multiply that by four. A triangular pyramid that has four equal triangles is also called a tetrahedron.
yes they have same area
yes
If you double (2 times) the perimeter the area will will be 4 times larger. Therefore the area is proportional to the square of the perimeter or the perimeter is proportional to the square root of area. The relationship as shown above applies only to triangles with similar proportions, that is when you scale up or down any triangle of fixed proportions. Other than that requirement, there is no relationship between perimeter and area of any shape of triangle except that it can be stated that the area will be maximum when the sides are of equal length (sides = 1/3 of perimeter).
1 method is to multiply length times the width and the 2 method is to divide the rectangle into triangles and find the area of one of the triangles and multiply the area by two.
Only if the two triangles are congruent will they have equal areas. A third fact is required to determine they are congruent (and thus have the same area): 1) The third sides are equal; 2) The angles enclosed between the sides are equal; or 3) The same one of the sides is the hypotenuse of the triangles, which are right angled triangles.
Yes.
Yes, any quadrilateral can be divided into two equal triangles by drawing a diagonal between two of its vertices. This diagonal splits the quadrilateral into two triangles, which can have equal areas if the diagonal divides the shape symmetrically. However, not all quadrilaterals will result in two equal-area triangles unless specific conditions are met regarding their dimensions or angles.
Yes, they do.
I believe so, though I am not sure I can prove it.
Given:In a triangle ABC in which EF BC To prove that:AE/EB=AF/FC Construction:Draw EX perpendicular AC and FY perpendicular AB Proof:taking the ratios of area of triangle AEF and EBF and second pair of ratio of area of triangle AEF and ECF. We get AE/EB and AF/FC we know that triangle lie b/w sme and same base is equal in area therefore area of EBF I equal to area of ECF therefore AE/EB=AF/FC HENCE PROVED
Any triangles where the base multiplied by the height equal 2, so technically, infinity.
The total area of the garden can be determined by calculating the area of one of the triangles and then multiplying that area by 6, since the garden is divided into 6 equal triangles. If the area of one triangle is known, simply multiply it by 6 to find the total area of the garden. Without the specific area of one triangle, the total area cannot be determined numerically.
The area of the circle is equal to the combined area of the rectangles formed by cutting the circle into equal-sized triangles and placing them together side by side. This is because the circumference of the circle is equal to the perimeter of the rectangles, which means the area enclosed by the circle is equal to the area of the rectangles. This concept is known as the "circle packing theorem" in mathematics.
only for triangles and parallelograms as far as i know
A=1/2bh The area of a triangle is 1/2bh. If the base of it is a triangle and all 4 of the triangles aren't the same, then you have to find the area of the base triangle and then the three other triangles (which should all have the same area). If all four of the triangles have the same area, then just find the area of one of the triangles and multiply that by four. A triangular pyramid that has four equal triangles is also called a tetrahedron.
There is not enough information about the triangles to be able to answer the question.