1 6 15 20 15 6 1
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The sum of the numbers on the fifteenth row of Pascal's triangle is 215 = 32768.
64
The terms in row 29 are: 29Cr = 29!/[r!*(29-r)!] for r = 0, 1, 2, ... 29 where r! denotes 1*2*3*...*r and 0! = 1
The rth term of the 25th row is 25!/[r!(25-r)!] where r = 0,1,2,...,25 and k! denotes 1*2*3*...*k and 0! = 1 So 1 25 300 2,300 12,650 53,130 177,100 480,700 1,081,575 2,042,975 3,268,760 4,457,400 5,200,300 and then the same numbers in reverse order, all the way back to 1.
(1/2n-r)2+((n2+2n)/4) where n is the row number and r is the position of the term in the sequence