First, take the square root of 128 to find the side length. Use this with the Pythagorean theorem (a2 + b2 = c2) to find the length of the diagonal, which is the hypotenuse of a triangle that takes up half the area of the whole garden. The diagonal ends up being 16 m. The steps are a bit hard to write on this page, so I've included them in the "related links" section, below.
If the area of the square is 200, then the side is sqrt(200).The length of the diagonal is sqrt(200 + 200) = sqrt(400) = 20 meters.
Area = 64 cm2 so length of side = 8cm Then, by Pythagoras, length of diagonal = sqrt[82 + 82] = 8*sqrt(2) = 11.3137 cm (to 4 dp)
Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2
The formula for the area of a square is s2 (sides squared)
To find the length of the diagonal of a square with an area of 64 square units, we first need to calculate the side length of the square. Since the area of a square is side length squared (A = s^2), we can find the side length by taking the square root of the area (s = √A). In this case, the side length of the square is 8 units. To find the length of the diagonal, we can use the Pythagorean theorem, which states that the square of the length of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides (a^2 + b^2 = c^2). Since a square can be divided into two right triangles with the diagonal as the hypotenuse, we can calculate the diagonal length using d = √(s^2 + s^2), where d is the diagonal length and s is the side length. Substituting the side length of 8 units into the formula, we get d = √(8^2 + 8^2) = √(64 + 64) = √128 = 8√2 units. Therefore, the length of the diagonal of a square with an area of 64 square units is 8√2 units.
20m
The diagonal of a square whose area is 36 is the square root of 72, or about 8.49. Since the area of a square is side(squared), then the sides are each 6. Then since a(squared) + b(squared) = c(squared), for a triangle (the diagonal), you get the square root of 72.
The garden's diagonal is 10 meters.
The diagonal of the garden is 20 meters.
16 cm squared.
The diagonal is 14 inches.
The area of a square is length (of a side) squared.
It is 10 metres.
If the area of the square is 200, then the side is sqrt(200).The length of the diagonal is sqrt(200 + 200) = sqrt(400) = 20 meters.
10 meters
Using Pythagoras each side is 26*sq rt of 2 which is 1352 when squared. So area of the square is 1352 square inches
A square with an area of 80 acres has a length and width of 1,867 feet. The diagonal length of the square is 2,640 feet.