Area of a rectangular carpet = length x breadth = 5 x 2 = 10 sq ms
186.6 square yards of carpet are needed.
Let the breadth = xSo, length = 2x+1Thus perimeter will be,2(2x+1+x)=122= 6x+2=122So, 6x=122-2=120So, x= 120/6=20Therefore length=2x+1=2(20)+1=41
180 meters to 300 meters height length 14ft
Length is usually the longest dimension.
Having the length x meters and width 8 meters, then the area is 8x square meters.
Perimeter = 2*(Length + Breadth) So, 1570 = 2*(168 + Breadth) 785 = 168 + Breadth Breadth = 617 metres Which is rather an unusual result because normally the length is greater than the breadth.
length----8cm breadth---4cm
length by breadth by height in metres
2l+2w=24 l=2w 2(2w)+2w=24 4w+2w=24 6w=24 w=4 l=2w=2*4=8 Length is 8 meters, the width (or breadth) is 4 meters.
2l+2w=48 l=2w 2(2w)+2w=48 4w+2w=48 6w=48 w=8 l=2*8=16 So, the length is 16 meters and the width (or breadth) is 8 meters.
area=28.08 breadth[width]=3.6 length= a divided by b =28.08 divided by 3.6 = ................
9*7 = 63 square meters
We can calculate the area by taking out the product of the length and the breadth of the house
length x width Example: A rectangle has a length of 24m and a width of 48m. What is its area? l x w= 24m(length) x 48m(width/breadth) = 1152m2 (meters squared)
P = 416 so L + B = 208. 208 - 30 = 178, half of 178 = 89 which is the breadth, making the length 119, so the area is 89 x 119 ie 10591 sqm.
Give the length and width to calculate area: S = L x l
12 meters long, 5 meters wide. Diagonal = 13 meters. Solve and prove with Pythagorean therum : 12 squared (144) + 5 squared (25) = 13 squared (169).