L + W = P/2 = 72 feet
L = 3W so L = 3/4 x 72 = 54 feet
63 feet
the length is equal to 160,083
No. If you draw a rectangle there are four sides, the length of two of those sides are equal to the length, and the other two are equal to the width. Therefore: the perimeter, which is equal to all the sides added up, is equal to two times the length plus two times the width: or 2L+2W= Perimeter. If you know L and you know the perimeter you can solve it algebraically. the width equals the perimeter minus two times the length, all that divided by two, or W= (P-2L)/2 (when you do the algebra). you might be thinking about the area in which case if you knew the area and the length and you want to find the width you would divide the area by the length.
A rectangle with a perimeter of 48 and 1 side equal to 5 would have its other sides lengths of 5, 19, 19. Such a rectangle would have an area of 95 sq/m. Your question is somewhat strange, as the "length" of a rectangle generally refers to the longer side - in this case the length would be 19 and the width 5.
A rectangle has two pairs of equal sides. So to calculate the perimeter, add two known sides and multiply by two. 45 + 10 = 55 55 x 2 = 110 Perimeter - 110 metres.
No rectangle can have equal perimeter and length.
15 feet.
63 feet
the length is equal to 160,083
The perimeter of any rectangle is [ 2 x (length + width) ]. Since the length and width of a square are equal, the perimeter of a square is also [ 2 x (side + side) ] = (4 x side).
A rectangle by definition has two pairs of sides with equal length. Since perimeter equals the length of all the sides. The equation for the perimeter of a rectangle could be thought of as: 2L + 2W = P Where L represents the length of one side of the rectangle and W represents the length of the adjacent (next to) side of the rectangle. If you know the length of one side and the perimeter, plug those values in as L and P and then solve for W. That will give you L and W which are the dimensions of the rectangle.
Since by definition, a rectangle has two pairs of equal length sides, (2 * 7) + (2 * 45) will get the perimeter: 104.
A rectangle has 2 pairs of equal sides, so it would be 2X2+2X4=12
These two plane figures do not have a common perimeter. As the opposite sides of a rectangle are of equal length then only the measurements of two adjacent sides are needed to calculate the perimeter. (Perimeter = 2A + 2B, where A and B are the lengths of adjacent sides) However, a trapezium does not necessarily have any of its sides of equal length and therefore all four sides have to be measured to determine the perimeter.
Perimeter = length + length + width + width Let "w" = width, then "7w" must equal the length (because it's 7 times the width) 7w + 7w + w + w = perimeter 16w = perimeter
the perimeter is the sum of the length of every side of the geometrical figure. In your case, since you have 4 sides two of which are equal, the perimeter would be 2*(a+b) where a and b are the length of two sides
No. If you draw a rectangle there are four sides, the length of two of those sides are equal to the length, and the other two are equal to the width. Therefore: the perimeter, which is equal to all the sides added up, is equal to two times the length plus two times the width: or 2L+2W= Perimeter. If you know L and you know the perimeter you can solve it algebraically. the width equals the perimeter minus two times the length, all that divided by two, or W= (P-2L)/2 (when you do the algebra). you might be thinking about the area in which case if you knew the area and the length and you want to find the width you would divide the area by the length.