Well, isn't that just a happy little problem we have here? To find the area of the rectangle, we first need to use the Pythagorean theorem to find the length and width. Since the length is twice the width, we can set up the equation x^2 + (2x)^2 = 25^2. Solving this will give us the width and length, and then we can multiply them to find the area. Happy calculating!
The width will be 30cm
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The diagonal is 20.
The width will be 30cm
The diagonal is 26cm
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
Width is 5.
The length of the diagonal is about 16.03 feet.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The diagonal is 20.
The diagonal length is about 18.44 inches.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
Diagonal = 10 meters.
The diagonal is 3.61cm