Let length be 2x and the width be x and use Pythagoras' theorem:
2x2+x2 = 252
3x2 = 625
Divide both sides by 3 and then square root both sides:
x = 14.43375673 cm
2x = 28.86751346 cm
Area = 2x*x = 416 and 2/3 square cm
The width will be 30cm
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The diagonal is 20.
The width will be 30cm
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
The length of the diagonal is about 16.03 feet.
Width is 5.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The diagonal is 20.
The diagonal length is about 18.44 inches.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
Diagonal = 10 meters.
The diagonal is 3.61cm