Let length be 2x and the width be x and use Pythagoras' theorem:
2x2+x2 = 252
3x2 = 625
Divide both sides by 3 and then square root both sides:
x = 14.43375673 cm
2x = 28.86751346 cm
Area = 2x*x = 416 and 2/3 square cm
The width will be 30cm
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The diagonal is 20.
The width will be 30cm
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
The diagonal is 26cm
The length of a rectangle that has a diagonal of 25 feet and a width of 15 feet is 20 feet.
The length of the diagonal is about 16.03 feet.
Width is 5.
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
The diagonal is 20.
The diagonal length is about 18.44 inches.
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
Diagonal = 10 meters.