It is (x - 4)^2 + (y + 3)^2 = 2^2or x^2 + y^2 - 8x + 6y + 21 = 0
No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2No. The resulting equation has more solutions. For example, x = 2 has only one solution and that is x = 2.butx2= 4, the squared equation, has two solutions: x = +2 and x = -2
Use the standard slope/intercept equation for a straight line and substitute the figures given in the question. y = mx + c .......m is the slope so we can now write y = -5x + c Substituting the ordered pair for x and y gives : 2 = (-5*0) + c = c The final equation is therefore, y = -5x + 2
If y = -3x - 2 then substituting x from each ordered pair gives :- A) (1,1) y = (-3*1) - 2 = -5 ☒ B) (0,-1) y = (-3*0) - 2 = -2 ☒ C) (0,0) y = (-3*0) - 2 = -2 ☒ D) (-1,0) y = (-3*-1) - 2 = 1 ☒ So the answer is ALL OF THEM are not solutions to the equation y = -3x - 2.......BUT, you've used the word Inequality so depending whether y > -3x - 2 or y < -3x -2 clearly affects the results.
AnFind the midpoint of the segment below and enter its coordinates as an ordered pair. (-3,4) (-3,-2)
There are infinitely many ordered pairs: each point on the straight line defined by the equation is an ordered pair that is a solution. One example is (0.5, 2.5)
7-4-14
x = 12 y = 2 (12,2) satifies the equation
A solution (in 2-dimensional space).A solution (in 2-dimensional space).A solution (in 2-dimensional space).A solution (in 2-dimensional space).
I have a hunch that this was originally a multiple-choice question, and you haven't given us the list of choices along with the question. There are an infinite number of ordered pairs that solve this equation. Go back to the list under the question, find the ordered pair where the 'y' number is 2 more than the 'x' number, and that's your solution.
One possible solution is x2 + (y - 4)2 = 0.
There are several solutions....what are the choices you have? Guessing one of them is (1,-4) or possibly (-1,-5). --Algebra 2 Teacher
It is (x - 4)^2 + (y + 3)^2 = 2^2or x^2 + y^2 - 8x + 6y + 21 = 0
The pair of equations: x + y = 1 and x + y = 3 have no solution. If any ordered pair (x,y) satisfies the first equation it cannot satisfy the second, and conversely. The two equations are said to be inconsistent.
There are an infinite number of ordered pairs. Any point on the straight line which passes through (0,4) and has a gradient of -2 will be an ordered pair for the equation.
-2,4
An ordered pair or coordinates of a point in 2-dimensional space.