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Which equation is an equation of a circle with a radius of 2 and its center at begin ordered pair 4 comma negative 3 end ordered pair?
Wiki User
∙ 8y ago
It is (x - 4)^2 + (y + 3)^2 = 2^2or
x^2 + y^2 - 8x + 6y + 21 = 0
Wiki User
∙ 7y ago
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How do you write an equation for a circle with a center?
Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
If a circle is centered at the origin and the length of its radius is 6 What is the circle's equation?
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
What is the equation of the circle with center (-3.2 -2.1) and radius 4.3?
The equation of the circle is: (x+3.2)^2 +(y+2.1)^2 = 18.49
How do you write the equation of a circle?
The general equation for the circle - or one of them - is: (x - a)^2 + (y - b)^2 = r^2 Where: a and b are the coordinates of the center r is the radius
What is the equation of the circle that touches the x axis when its center is at 2 5?
Center of circle: (2, 5) Point of contact with the x axis: (2, 0) Distance from (2, 5) to (2, 0) equals 5 which is the radius of the circle Equation of the circle: (x-2)^2 +(y-5)^2 = 25
Where is the center of the circle given by the equation (x plus 7)2 plus (y - 5)2 16 Enter your answer as an ordered pair.?
The center of the circle is at (-7, 5)
Where is the center of the circle given by the equation x plus 4 2 plus y -3 2 equals 4 Enter your answer as an ordered pair?
(-4,3)
How do you write an equation for a circle with a center?
Equation of any circle, with any radius, and its center at any point: [ x - (x-coordinate of the center) ]2 + [ y - (y-coordinate of the center) ]2 = (radius of the circle)2
What is the standard form of an equation where the poin 3-6 is on a circle whose orgin is the center?
9
What is the equation of the circle with center 2 9 and radius 7?
depends on the equation.
Where is the center of the circle given by the equation x plus 4 2 plus y plus 6 2 equals 49 Enter your answer as an ordered pair?
(-4, -6)
If a circle is centered at the origin and the length of its radius is 6 What is the circle's equation?
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
What is the equation for a circle with a center of (0 0) and a radius of 9?
The equation of the circle is: x^2 + y^2 = 81
Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 equals 25 Enter your answer as an ordered pair?
It's at the point ( -5, 3 ) The general formula of a circle is given by the equation: ( x - h )2 + ( y - k )2 = r2 Where the point ( h, k ) is the center of the circle, and r is the radius of the circle. In the equation ( x + 5 )2 + ( y - 3 )2 = 25 The first group of terms isn't subtracted. Rather than x + 5, this is actually x - -5. The center of the circle, then, is the point ( -5, 3 )
How do you write an equation in standard form of a circle with a center and radius?
The standard equation of a circle, with center in (a,b) and radius r, is: (x-a)2 + (y-b)2 = r2
What is the equation of a circle whose center is at the origin and whose radius is 10?
The equation of circle is (x−h)^2+(y−k)^2 = r^2, where h,k is the center of circle and r is the radius of circle. so, according to question center is origin and radius is 10, therefore, equation of circle is x^2 + y^2 = 100
Where is the center of the circle given by the equation x plus 5 times 2 plus y - 3 times 2 equals 25 in an ordered pair?
Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.
