False because the area of a trapezoid is: 0.5*(sum of its parallel sides)*height
You must first know the lengths of the top and bottom of the trapezoid. At this point, you must average those lengths and that is your midsegment length.
You must first know the lengths of the top and bottom of the trapezoid. At this point, you must average those lengths and that is your midsegment length.
It is the average of the bases.
Yes
It is 20 units.
Area of a trapezoid = 0.5*(sum of parallel sides)*height
No, the length of the midsegment of a trapezoid is equal to the average of the lengths of the bases. The sum of the lengths of the bases would typically yield a longer length than the midsegment.
You must first know the lengths of the top and bottom of the trapezoid. At this point, you must average those lengths and that is your midsegment length.
You must first know the lengths of the top and bottom of the trapezoid. At this point, you must average those lengths and that is your midsegment length.
It is the average of the bases.
Yes
It is 20 units.
It is (7 + 15)/2 = 11 units of length.
you just take the length of it's midsegment and multiply it by its height to find area. to find it's perimeter, just add the measures of it's sides
Yes. The midsection is equal to the average of the two bases.
The Trapezoid midsegment conjecture- the midsegment of a trapezoid is parallel to the bases and is equal to the length to the average of the lengths of the bases. This is Some what Algebra....... what you do is take your length 90 and midsegment 85 into a prob like this (90+X)/2=85 times by two on both sides to cancel out the two. after that you end up with 90+X=85 next you have to "isolate" the X by subtracting 90 from both sides you would get 90+X=85 -90 -90 to get X= -5 the other side would be -5 so it doesnt work to check it plug the number back into the equation (90+-5)/2=85
Length times width