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Pythagoras developed the method to solve this- A squared plus B squared equals C squared. A squared= 8x8, added to B squared (also 8x8) So that is 64+64 or 128. So 128 is line C squared. Find the square root of 128, and you have C, which is the diagonal. (Hint- it is 11.31)
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How long is the diagonal of a rectangle with dimensions 16 inches by 21 inches?
26.4 inches for the diagonal.
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4 feet height and 7 feet width is 91.8 inches diagonal means what is the diagonal of 4 feet height and 8 feet width?
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26.4 inches for the diagonal.
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A=l*w A=8*4 A=32 diagonal cuts the rectangle into two congruent triangles. 32/2 = 16
What is the diagonal of 12 inches and 5 inches?
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The diagonal of a rectangular box is 12 inches long One side of the box is 8 inches long What is the length of the other side?
8.9
What is the diagonal distance of a rectangle with the sides measuring fourteen feet ten inches by fifteen feet ten inches?
14 ft 10 inches = 178 inches 15 ft 10 inches = 190 inches By Pythagoras's theorem, diagonal2 = 1782 + 1902 = 67784 So diagonal = 260.35 inches (approx) or 21 feet 8 inches.
What is the diagonal measure of a rectangle 65 inches by 69 inches?
The square of the diagonal is (652+692)=8986 The diagonal is then the square root of 8986=94.79...
If a square has sides which are 2 inches how many inches is the length of the diagonal?
A square with 2-inch sides has a diagonal of: 2.828 inches.
How long is the diagonal of a square if each side is 12 inches long?
The diagonal is about 16.97 inches long.
