Their geometric mean is:sqrt(42*(1/9)2)=sqrt(16*(1/81))=sqrt(16/81)=4/9-------------------The geometric mean of a set of n terms is equal to the nth root of the product of those n terms. The geometric mean of 4 and 1/9 is sqrt(4*(1/9)) = sqrt(4/9) = 2/3.
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good question it took me forever to find one ,but i found two take your pick * JLO cocycle * John ellipsoid * Jump Piscontinuity i hope we helped you! =)
are you asking for help on finding definition for geometric terms? if so go to: http://library.thinkquest.org/2647/geometry/glossary.htm#b and to wikipedia for x and j terms
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Geometric Sequences work like this. You start out with some variable x. Your multiplication distance between terms is r. Your second term would come out to x*r, your third x*r*r, and so on. If there are n terms in the sequence, your final term will be x*r^(n-1).
· acute angle
There are a few geometric terms that start with the letter G including great circle, glide, and golden ratio. Another example is golden mean.
An arithmetic series is the sequence of partial sums of an arithmetic sequence. That is, if A = {a, a+d, a+2d, ..., a+(n-1)d, ... } then the terms of the arithmetic series, S(n), are the sums of the first n terms and S(n) = n/2*[2a + (n-1)d]. Arithmetic series can never converge.A geometric series is the sequence of partial sums of a geometric sequence. That is, if G = {a, ar, ar^2, ..., ar^(n-1), ... } then the terms of the geometric series, T(n), are the sums of the first n terms and T(n) = a*(1 - r^n)/(1 - r). If |r| < 1 then T(n) tends to 1/(1 - r) as n tends to infinity.
Geometric series may be defined in terms of the common ratio, r, and either the zeroth term, a(0), or the first term, a(1).Accordingly,a(n) = a(0) * r^n ora(n) = a(1) * r^(n-1)
a+a*r+a*r^2+...+a*r^n a = first number r = ratio n = "number of terms"-1
One geometric term that starts with the letter J is justification. It is a definition, postulate, or theorem that is used to draw a conclusion.
Their geometric mean is:sqrt(42*(1/9)2)=sqrt(16*(1/81))=sqrt(16/81)=4/9-------------------The geometric mean of a set of n terms is equal to the nth root of the product of those n terms. The geometric mean of 4 and 1/9 is sqrt(4*(1/9)) = sqrt(4/9) = 2/3.
You could use width and get away with it! It's worth a try.
It is not possible to answer this question without information on whether the terms are of an arithmetic or geometric (or other) progression, and what the starting term is.
The formula to find the sum of a geometric sequence is adding a + ar + ar2 + ar3 + ar4. The sum, to n terms, is given byS(n) = a*(1 - r^n)/(1 - r) or, equivalently, a*(r^n - 1)/(r - 1)