An equation where j = 3
5
Known equation: 3x+5y = 6 or y = -3/5x +6/5 Slope of equation: -3/5 Slope of parallel equation: -3/5 Parallel equation: y-1 = -3/5(x-3) => 5y = -3x+14 Parallel equation in its general form: 3x+5y-14 = 0
The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0
The x-intercept is where y = 0 → 6x + 5(0) - 3 = 0 → 6x = 3 → x = 0.5 The y-intercept is where x = 0: → 6(0) + 5y - 3 = 0 → 5y = 3 → y = 0.6
If the equation is 7x - 3y = 21 then (3, 0) and (0, -7).
2x + 5y = 2-3x - y = -3from the second equation:-y = -3 + 3xy = 3 - 3xsubstitute this value in the first equation:2x + 5(3-3x) = 22x + 15 - 15x = 2-13x + 15 = 2-13x = 2 - 15-13x = -13so, x = 1Now, solve for y :y = 3 - 3xy = 3 - 3 (1)y = zero
x=3 y=2 z=6
The equation 9=3y has the x-intercept (0,0) and the y-intercept (0,3).
2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
Using the quadratic equation formula: x = -1/4 and x = 2/3
None because the discriminant of this quadratic equation is less than zero.
-11
Assuming the two equations are: 3xy - 3 = 0 ............................................. 1 2xy = 0 ............................................. 2 Then from eq 1 xy = 1 from eq 2 xy = 0 That is not possible. Or, assuming the equation is 3xy - 3 + 2xy = 0 Then 5xy = 3 or y = 3/5x Substitute for any value of x to get the value of y
The result will be a plane that intercepts the x-, y-, and z-axes at +9, +6, and +3, respectively.
Let us say you X intercepts are -2 and 3 set up (X + 2)(X - 3) FOIL X^2 - X - 6 = 0 ----------------------- your parabolic equation
One simple solution is y = (x + 5/2)*(x - 2)*(x - 3/2) You can expand that into its cubic form, if you wish.