b to the fourth power
(a+b)2
4
The quadric equation is: negative b plus or minus the square root of b squared minus 4ac all over(divided by) 2a
(a+b)(a+b)Also equal to a2+2ab+b2
It simplifies to 5a+4 !
yes
-b + or - the square root of b squared - 4ac over/divided by 2a
The square root of ( a squared plus b squared ), quantity divided by a, where a is the length of the semi-major axis and b is the length of the semi-minor axis.
The square root of ( a squared plus b squared ), quantity divided by a, where a is the length of the semi-major axis and b is the length of the semi-minor axis.
The square root of ( a squared plus b squared ), quantity divided by a, where a is the length of the semi-major axis and b is the length of the semi-minor axis.
he made the theorem C squared = A squared + B squared and A squared = C squared - B squared or B squared = C squared - A squared
a(squared)+b(squared)=c(squared) The largest number is the c, and you can choose the a and b, since you need to find the a or the b. For example: You have the numbers 3, and 5 and you needed to find b. a(squared+b(squared)=c(squared) 3(squared)+b(squared)=5(squared) 9+b(squared)=25 -9 -9 b(squared)=16 Then take the square root b=4
It is: 2b squared
It is b*b
if you mean a right triangle then the formula is a squared + b squared = c squared. a and b are the legs and c is the hypotunese. the legs are the smallest number then the hypotenese. An example is a=3 , b= ? and c =5 use the formula : a squared + b squared = c squared 3 squared + b squared = 5 squared 9 + b squared = 25 -9 - 9 _________________________________________ b squared = 16 Then you have to take the squared root of 16 which is 4 and 4 is b squared.
b to the fourth power