Basically radius of gyration of a substance is defined as that distance from the axis of rotation from which if equivalent mass that of the substance is kept will have exactly the same moment of inertia about that axis of the substance.
I believe it is I = mk^2 where k is radius of gyration and m is mass.
to get the diameter from the radius you simply multiply the radius by 2 since the radius is half the diameter. d=2r where d = diameter and r = radius
The radius of the circle.
"Coordinates" on a grid or graph are numbers that describe a location. There's no physical significance to the process of multiplying two locations, and the procedure is undefined.
A= Area of the circle¶= Pi (About 3.14)r= Radius squared (Radius times radius)3.14 * Radius squared
No. Radius of gyration depends upon the axis of rotation of the body.
For a solid cylinder, divide the radius of the flywheel by the square root of 2, to get the radius of gyration.
I believe it is I = mk^2 where k is radius of gyration and m is mass.
The radius of gyration is a measure, in mechanics, of the distribution of mass in an object relative to its centre of mass or a specified axis of rotation.
i thing radius of gyration does not depend upon mass because it is the distance between reference axis and the centre of gravity.
radius of gyration = sqrt(Moment of inertia/cross section area) Regards, Sumit
Radius of gyration is the distance from the centre of gravity to the axis of rotation to which the weight of the rigid body will concentrate without altering the moment of inertia of that particular body.
It is the square root of ratio moment of inertia of the given axis to its mass.
The Radius of Gyration of an Area about a given axis is a distance k from the axis. At this distance k an equivalent area is thought of as a line Area parallel to the original axis. The moment of inertia of this Line Area about the original axis is unchanged.
Gyration is a noun. It was obvious that the crushed top had had it's last gyration. Our Earth makes one complete gyration per day.
I=mr2 therefore r = root (I/m) = root (5/45) = 0.333 recuring
If they have the same radius of gyration (k) they will accelerate at the same rate.If not the ball with the lesser k would accelerate more quickly.