I believe it is I = mk^2 where k is radius of gyration and m is mass.
Basically radius of gyration of a substance is defined as that distance from the axis of rotation from which if equivalent mass that of the substance is kept will have exactly the same moment of inertia about that axis of the substance.
Its diameter is 2R, whatever the mass.
Along the height it is hb^3/48 and along base it is bh^3/36
making the beam more solid by using more material or material with a higher density. Also, you could deflate the air out of it so it has less tendency to rise with hot air currents.
Second moment of area for triangle trough x-axis = (ah3)/36
It is the square root of ratio moment of inertia of the given axis to its mass.
radius of gyration = sqrt(Moment of inertia/cross section area) Regards, Sumit
In structural engineering, the relationship between beam deflection and moment of inertia is that a higher moment of inertia results in less beam deflection. Moment of inertia is a measure of an object's resistance to bending, so beams with a higher moment of inertia are stiffer and deflect less under load. This relationship is important in designing structures to ensure they can support the intended loads without excessive deflection.
The relationship between the moment of inertia and angular acceleration (alpha) in rotational motion is described by the equation I, where represents the torque applied to an object, I is the moment of inertia, and is the angular acceleration. This equation shows that the torque applied to an object is directly proportional to its moment of inertia and angular acceleration.
Basically radius of gyration of a substance is defined as that distance from the axis of rotation from which if equivalent mass that of the substance is kept will have exactly the same moment of inertia about that axis of the substance.
The Radius of Gyration of an Area about a given axis is a distance k from the axis. At this distance k an equivalent area is thought of as a line Area parallel to the original axis. The moment of inertia of this Line Area about the original axis is unchanged.
The formula for radius of gyration is given by (k = \sqrt{\frac{I}{m}}), where (k) is the radius of gyration, (I) is the moment of inertia of the object, and (m) is the mass of the object. Radius of gyration is the distance from the axis of rotation where the entire mass of an object is considered to be concentrated.
The moment of inertia for point particles is directly related to their distance from the center of mass. The farther a point particle is from the center of mass, the greater its moment of inertia.
The radius of gyration of a uniform cylinder is half of its radius, so for a cylinder with a radius of 0.43m, the radius of gyration would be 0.43m/2 = 0.215m. It is the distance from the axis of rotation where the mass of the cylinder may be concentrated without changing its moment of inertia.
I=mr2 therefore r = root (I/m) = root (5/45) = 0.333 recuring
is a resisstance of a body is called inertia
Mass moment of inertia measures an object's resistance to rotational motion due to its mass distribution, while area moment of inertia measures an object's resistance to bending due to its shape and cross-sectional area. Mass moment of inertia depends on both the mass and its distribution, while area moment of inertia depends on the shape and how the material is distributed in the cross-section.