Using Pythagoras' theorem it is 26 inches in length
26.4 inches for the diagonal.
15 inches (solved with the help of Pythagoras' theorem)
44 feet 4 inches
15 cm for the diagonal.
It would be 15 inches long.
26.4 inches for the diagonal.
Anything you want, so long as (Length in inches)2 + (Width in inches)2 = 1,764
The diagonal is 221.2 inches long.
15 inches (solved with the help of Pythagoras' theorem)
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
You use the pythagorous theorm to calculate the hypotenuse of the triangle, which is the same line as the diagonal. 7(7)+ 10(10)= diagonal x diagonal 149= diagonal x diagonal Diagonal= square root of 149: this approximates to 12.207in Visit quickanswerz.com for more math help/tutoring! Consider a rectangle with dimensions 7 inches by 10 inches. Let ABCD be the rectangle. We need to find the length of the diagonal. We know that the diagonals of a rectangle are same in length. So, it is enough to find the length of the diagonal BD. From the rectangle ABCD, it is clear that the triangle BCD is a right angled triangle. So, we can find the length of the diagonal using the Pythagorean Theorem. BD2 = BC2 + DC2 BD2 = 102 + 72 BD2 = 100 + 49 BD2 = 149 BD = √149 BD = 12.207 So, the length of the diagonal is 12.21 inches. Source: www.icoachmath.com
157.6102789 inches
44 feet 4 inches
The diagonal of a rectangle with the length of 30 yd and the width of 30 yd is approximately 42.43 yd
15 cm for the diagonal.
If the only known fact is the length of the diagonal then the width and length of the rectangle CANNOT be determined. The diagonal could be that of a square, or of a rectangle that is very long but quite narrow. Consequently at least one more fact is required such as; the dimension of either the length or the width, or the angle that the diagonal makes to the base of the rectangle or even the area of the rectangle.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.