The width of the rectangle is 8. 48/6 = 8
8 and 6
The area of a rectangle is found by using the formula A=LxW (Area equals length times width)The area of a rectangle is calculated by multiplying the length by the width - the result is square measure. A rectangle 6 inches by 8 inches would be 48 square inches in area. (6x8=48)ExampleA=LxWA=4x5A=20
The length is 12 cm and the width is 4 cm and so 12*4 = 48 square cm
The diagonal of a rectangle with the length of 89.5 inches and a width of 48 inches is approximately 101.6 inches.
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
Let x be the width of the rectangle. Then the length is 3x. The area of the rectangle is 3x * x = 3x^2, which also has to be 48. Solving for x, we get that the width is 4, and the length is 12.
8 and 6
Approximately 5.2115 and 9.2115
The width is 6 feet. The length is 8 feet.
48 / 16 = 3
3 cm
The area of a rectangle cannot be 48 feet since that is NOT a measure of area. Area is measured in square units.
48 feet. You just multiply the width times the length.
7 x 17
The area of a rectangle is found by using the formula A=LxW (Area equals length times width)The area of a rectangle is calculated by multiplying the length by the width - the result is square measure. A rectangle 6 inches by 8 inches would be 48 square inches in area. (6x8=48)ExampleA=LxWA=4x5A=20
One possibility is that it could have a length of 12 cm and a width of 4 cm
6 cm