297 M
In a regular polygon, the apothem is a line from the centre to the mid-point of one of the flat sides. The radius is a line from the centre to a corner, which is longer.
Such a hexagon is impossible. A regular hexagon with sides of 2 cm can have an apothem of sqrt(3) cm = approx 1.73.It seems you got your question garbled. A regular hexagon, with sides of 2 cm, has an area of 10.4 sq cm. If you used your measurement units properly, you would have noticed that the 10.4 was associated with square units and it had to refer to an area, not a length.
A regular pentagon with a radius (apothem) of 5.1 units cannot have sides of 7.5 units and, conversely, a regular pentagon with sides of length 7.5 units cannot have a radius of 5.1 units. The figure is, therefore, impossible.
The question cannot be answered. A regular hexagon with sides of 10 inches would have apothems of 10/sqrt(2) = 7.071 inches. Therefore the hexagon cannot be regular. And, since the hexagon is irregular, there is not enough information to answer the question.
The hexagon will consist of 6 equilateral triangles of 3 equal sides of 10 cm and the apothem will divide the triangle into 2 right angle triangles with a base of 5 and an hypotenuse of 10 and so by using Pythagoras' theorem the height of the triangle which is the apothem works out as 5 times square root of 3 or about 8.66 cm rounded to 2 decimal places.
In a regular polygon, the apothem is a line from the centre to the mid-point of one of the flat sides. The radius is a line from the centre to a corner, which is longer.
3.55
Such a hexagon is impossible. A regular hexagon with sides of 2 cm can have an apothem of sqrt(3) cm = approx 1.73.It seems you got your question garbled. A regular hexagon, with sides of 2 cm, has an area of 10.4 sq cm. If you used your measurement units properly, you would have noticed that the 10.4 was associated with square units and it had to refer to an area, not a length.
We know that the height of an equilateral triangle equals the product of one half of the side length measure with square root of 3.Since in our regular hexagon we form 6 equilateral triangles with sides length of 16 inches, the apothem length equals to 8√3 inches.
A regular pentagon with a radius (apothem) of 5.1 units cannot have sides of 7.5 units and, conversely, a regular pentagon with sides of length 7.5 units cannot have a radius of 5.1 units. The figure is, therefore, impossible.
The question cannot be answered. A regular hexagon with sides of 10 inches would have apothems of 10/sqrt(2) = 7.071 inches. Therefore the hexagon cannot be regular. And, since the hexagon is irregular, there is not enough information to answer the question.
A regular hexagon, like any other hexagon, has six sides.
4 times the square root of 3. Use an equilateral triangle and 30-60-90 triangles.
If the hexagon's sides and angles are congruent, then it a regular hexagon.
No. A regular hexagon has 6 equal sides and angles.A heptagon has 7 sides.
The hexagon will consist of 6 equilateral triangles of 3 equal sides of 10 cm and the apothem will divide the triangle into 2 right angle triangles with a base of 5 and an hypotenuse of 10 and so by using Pythagoras' theorem the height of the triangle which is the apothem works out as 5 times square root of 3 or about 8.66 cm rounded to 2 decimal places.
A hexagon with 6 congruent sides is a regular hexagon