Equation: 4x^2 +4y^2 +16x -32y +71 = 0
Divide all terms by 4: x^2 +y^2 +4x -8y +71/4 = 0
Complete the squares: (x+2)^2 +(y-4)^2 -4 -16 +71/4 = 0
So: (x+2)^2 +(y-4)^2 = 9/4 which is the radius squared
Therefore centre of circle is at (-2, 4) and its radius is 3/2 or 1.5
Equation: x^2 + y^2 +10x -14y +10 = 0 Completing the squares: (x+5)^2 + (y-7) -25-49 +10 = 0 So: (x+5)^2 + (y-7) = 64 Therfore the circle's centre is at (-5, 7) and its radius is 8
Equation of circle: x^2 +y^2 -4x -6y -3 = 0 Completing the squares: (x-2)^2 +(y-3)^2 = 16 square units Therefore center of circle is at (2, 3) and its radius is 4 units
x^2 + y^2 = 100 (x - 0 )^2 + ( y - 0)^2 = 10^2 This is now in the Pythagorean form. x^2 + y^2 = r^2 The centre in Cartesian coordinates is the displacement of (x,y). Since there is no displacement , the the centre is at (0,0) r^2 is the radius squared at 10^2 , then the radius has a length of '10'.
(x + 9)^2 + ( y + 5)^2 = 64 = 8^2 This is in the Pythagorean form of a^2 + b^2 = r^2 The displacement of 'x' is '-9' and the displacement of 'y' is '-5' Hence the centre as ( x,y) is (-9, -5) The radius is 'r at '8 units'.
well it means that if u square something that's is all i know
The centre is (a, a) and the radius is a*sqrt(2).
Centre = (0,0), the origin; radius = 11
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
A circle, centre (0,0), radius = 5
The centre is (3,-1) and the radius is sqrt(10).
A circle centre (0, 0) and radius r has equation x² + y² = r² The circle x² + y² = 36 has: r² = 36 → radius = 6
5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.
Radius = 1111
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
If that equals 16 then the radius is 4
4