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What is the center and radius of the circle with equation (x plus 9)2 (y plus 5)2 64?
Wiki User
∙ 8y ago
(x + 9)^2 + ( y + 5)^2 = 64 = 8^2
This is in the Pythagorean form of a^2 + b^2 = r^2
The displacement of 'x' is '-9' and the displacement of 'y' is '-5'
Hence the centre as ( x,y) is (-9, -5)
The radius is 'r at '8 units'.
lenpollock
Wiki User
∙ 8y agoCentre = (-9, -5)Radius = 8
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