0
What is the center and radius of the circle with equation (x plus 9)2 (y plus 5)2 64?
(x + 9)^2 + ( y + 5)^2 = 64 = 8^2
This is in the Pythagorean form of a^2 + b^2 = r^2
The displacement of 'x' is '-9' and the displacement of 'y' is '-5'
Hence the centre as ( x,y) is (-9, -5)
The radius is 'r at '8 units'.
What else can I help you with?
What is the center and the radius of the circle x2 plus y2 -4x -6y -3 equals 0?
Equation of circle: x^2 +y^2 -4x -6y -3 = 0 Completing the squares: (x-2)^2 +(y-3)^2 = 16 square units Therefore center of circle is at (2, 3) and its radius is 4 units
What is the centre and radius of the circle x squared plus y squared plus 10x -14y plus 10 equals 0?
Equation: x^2 + y^2 +10x -14y +10 = 0 Completing the squares: (x+5)^2 + (y-7) -25-49 +10 = 0 So: (x+5)^2 + (y-7) = 64 Therfore the circle's centre is at (-5, 7) and its radius is 8
What is the length of tangent line from -2 3 to the point of contact with the circle x2 plus y2 plus 6x plus 10y minus 2 equals 0?
Equation of circle: x^2 +y^2 +6x +10y -2 = 0 Completing the squares: (x+3)^2 +(y+5)^2 = 36 Radius of circle: 6 Center of circle: (-3, -5) Distance from (-2, 3) to (-3, -5) is sq rt of 65 which is hypotenuse of a right triangle Using Pythagoras' theorem: square root of 65^2 -6^2 = 29 Therefore length of tangent line is the square root of 29 Note that the tangent line of any circle always meets its radius at right angles which is 90 degrees.
What is the equation of the tangent line that meets the circle x2 -4x plus y2 -6y equals 4 at the point 6 4?
Circle equation: x^2 -4x +y^2 -6y = 4 Completing the squares: (x-2)^2 +(y-3)^2 = 17 Point of contact: (6, 4) Center of circle: (2, 3) Slope of radius: 1/4 Slope of tangent line: -4 Tangent equation: y-4 = -4(x-6) => y = -4x+28 Tangent line equation in its general form: 4x+y-28 = 0
What is the radius of the circle whose equation is 3x² plus 3y² equals 75?
3x^2 + 3y^2 = 75 Divide both sides by '3' Hence x^2 + y^2 = 25 x^2 + y^2 = 5^2 In the Pythagorean Geometry The circle equation is x^32 + y^2 = r^2 Hence 5^2 = r^2 Hence r = 5 (The radius)
X2 plus y2 equals 64. what is the radius?
That's the equation of a circle with its center at the origin and a radius of 8.
What is the center and the radius of the circle with this equation x2 plus y2 equals 121?
Centre = (0,0), the origin; radius = 11
Find the center and radius of the circle with this equation x2 plus y2 plus x equals 0?
x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5
What is x square plus y square equals 36?
It is the equation of a circle with radius of 6 and its center at the origin.
What are the center and radius of the circle defined by the equation x2 plus y2-6 plus 8y plus 210?
Without an equality sign it can't be considered to be an equation but in general the equation of a circle whose centre is at (a, b) and radius is r is:- (x-a)^2+(y-b)^2 = r^2
Find the center and radius of the circle with this equation X2 plus Y2 minus 6X plus 2Y equals 0?
The centre is (3,-1) and the radius is sqrt(10).
The equation for the circle is x2 plus y2 equals 121 What is the length of the circle's radius?
Radius = 1111
Find the radius for a circle with the equation x2 plus y2 equals 9?
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
What is the radius for a circle with the equation x2 plus y2 equals 9?
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.
The equation of a circle centered at the origin is x2 plus y2 16. What is the radius of the circle?
If that equals 16 then the radius is 4
What is the radius for a circle whose equation is x2 plus y2 36?
If that means = 36 then then the radius of the circle is 6 units
The equation of the inner circle is x2 plus y2 equals 9 The radius of the outer circle is twice the radius of the inner circle What is the equation of the outer circle?
x^2+y^2=36
