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If a Displacement vectors of 4 km south 2 km north 5 km north combine to a total displacement of?
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
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If the displacement is negative 2 north and represents a positive displacement What is the direction?
south
A -2 displacement towards the north represents a positive displacement towards the south?
Indeed it is.
What is the total displacement of a child who walks 4m south 2m north 5m south and 5m north?
To find the total displacement, we need to calculate the net movement in the north-south direction. The child walks 4m south and 5m south, totaling 9m south, and then walks 2m north and 5m north, totaling 7m north. The net displacement is 9m south - 7m north = 2m south. Therefore, the total displacement of the child is 2m south.
Meg walks 5 blocks south and then turns around and walks 8 blocks back to the north. the distance that she walks is 13 blocks. what is her displacement?
Meg's displacement is the straight-line distance from her starting point to her ending point. She walks 5 blocks south and then returns 8 blocks north, resulting in a net movement of 3 blocks north from her original position. Therefore, her displacement is 3 blocks north.
What is the total displacement of a student who walks 3 blocks east 2 blocks north 1 block westand then 2 blocks south?
To calculate the total displacement, we can break down the student's movements into net east-west and north-south components. The student walks 3 blocks east, 1 block west (net 2 blocks east), and 2 blocks north, then 2 blocks south (net 0 blocks north). Therefore, the total displacement is 2 blocks east, resulting in a final displacement of 2 blocks east.
What are displacement vectors of 2 km south and 6 km north and 5 km south and 6 km north combine to a total displacement of?
2 km south
What is the correct displacement for the following vectors 4 km south km north 5 km south and 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the correct displacement for the following vectors 4 km south 2 km north 5 km south 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the correct displacement for the following vectors 4 km south 2 km north 5 km south .5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the correct displacement for the following vectors 4 km south 2 km north 2 km south and 5 km north?
The displacement is a shortest distance. Here, the displacement will be 1 km. It will be in the North direction.
What is the correct displacement for the following vectors 4km south 2km north 5km south and 5km north?
The total displacement is 2km north, as the southward and northward displacements cancel each other out.
What are not vectors?
north, 35 degrees north of east
If the displacement is negative 2 north and represents a positive displacement What is the direction?
south
A -2 displacement towards the north represents a positive displacement towards the south?
Indeed it is.
What is the displacement of a hiker who travels 3.0 km east and then 4.0 km north?
The displacement of the hiker can be found by treating the eastward and northward movements as vectors. Using the Pythagorean theorem, the displacement is the square root of the sum of the squares of the distances traveled in each direction. In this case, the displacement is √(3.0 km)^2 + (4.0 km)^2 = √(9 km^2 + 16 km^2) = √25 km^2 = 5.0 km. Therefore, the displacement of the hiker is 5.0 km in a direction that is 53.1 degrees north of east.
A car moved 50 km to the North. what is the displacement?
The displacement of the car is 50 km North. Displacement is a vector quantity that represents the shortest distance and direction from the initial to the final position of an object.
A dog walks 6m north 4m south What is the total displcement of the dog from the starting point?
The total displacement of the dog from the starting point can be calculated by finding the net displacement, which is the difference between the distances moved in each direction. In this case, the net displacement would be 6m north - 4m south, resulting in a total displacement of 2m north.
