A square with 2-inch sides has a diagonal of: 2.828 inches.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
The diagonal of a 20 inch square is the square root of 800 inches, approximately 28.284 inches, which is the sum of the squares of two sides.
If you take the square of the long side and add it to the square of the short side, you get the diagonal (hypotenuse) squared. Then just find square root of that. For example, if short side is 3cm and long side is 4cm: 9 + 16 = 25, so the diagonal would be the square root of 25 ie. 5.
25 of them.
The diagonal of a 101 inch square is about 142.84 inches.
The diagonal is 517.602 inches.
The diagonal of an 18 inch square is about 25.46 inches. (18 times the square root of 2).
The diagonal will be 49.739 inches.
Use Pythagoras' theorem to find the length of the diagonal in the square
About 21.2 inches.
A 12" x 12" square has a diagonal measurement of: 16.97 inches.
A square with 2-inch sides has a diagonal of: 2.828 inches.
A square with a 30-inch diagonal measurement has sides of 21.21 inches in length.
The diagonal of a 20 inch square is the square root of 800 inches, approximately 28.284 inches, which is the sum of the squares of two sides.
If you take the square of the long side and add it to the square of the short side, you get the diagonal (hypotenuse) squared. Then just find square root of that. For example, if short side is 3cm and long side is 4cm: 9 + 16 = 25, so the diagonal would be the square root of 25 ie. 5.
25 of them.