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What is the perimeter of a square when the length of the diagonal is 15 inches?
15 times the square root of two, all over two A formula is this: The diagonal for a square is always the sides of the square times the square root of 2
What is the diagonal of 11 square inches?
As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in
How is the length of a diagonal of a square found?
As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.
What is the length of the diagonal of a square with 36 inch sides?
sqrt (2 x 36 x 36) ie 50.94 inches
What is the length of the diagonal of a square whose area is 64 cm2?
The square's diagonal is 11.314 cm
